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Tcecarenko [31]
2 years ago
13

A bomb calorimeter, or a constant volume calorimeter, is a device often used to determine the heat of combustion of fuels and th

e energy content of foods. In an experiment, a 1.1480 g sample of maleic acid (C4H4O4) is burned completely in a bomb calorimeter. The calorimeter is surrounded by 1.042×103 g of water. During the combustion the temperature increases from 23.88 to 26.37 °C. The heat capacity of water is 4.184 J g-1°C-1. The heat capacity of the calorimeter was determined in a previous experiment to be 834.0 J/°C. Assuming that no energy is lost to the surroundings, calculate the molar heat of combustion of maleic acid based on these data.
C4H4O4(s) + 3O2(g) 2H2O(l) + 4CO2(g) + Energy
Chemistry
1 answer:
Ksju [112]2 years ago
4 0

Answer:

k

Explanation:

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8 0
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Why are the fruit and vegetable sections called the produce aisle?
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3 years ago
HELP!!!! ASAP!!! Fast please !!! Is this A. Closed parallel circuit B. Closed series circuit C. Open series circuit D. Open para
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3 years ago
Which is the limiting reactant if we start with 30.0 g Al and 30.0 h O2​
lorasvet [3.4K]

Al

Explanation:

The limiting reactant will be Al:

        4Al + 3O₂ → 2Al₂O₃

The limiting reactant is the reactant in short supply in a chemical reaction.

     Given parameters:

  Mass of Al = 30g  Molar mass = 27g/mol

         Number of moles = \frac{mass}{molar mass} =  \frac{30}{27}

         Number of moles of Al = 1.111 mole

  Mass of O₂ = 30g, molar mass = 32g/mol

   Number of moles =  \frac{30}{32} = 0.94mol

In the reaction:

          4 moles of Al reacted with 3 moles of O₂

         1.11moles of Al will require \frac{1.11 x3}{4} = 0.83mole to react

But we have been given 0.94mole of O₂. This is more than required.

Therefore O₂ is in excess and Al is the limiting reactant.

Learn more:

Limiting reagents brainly.com/question/6078553

#learnwithBrainly

4 0
3 years ago
What is the answer to this question
Stels [109]

Answer:

38 kg/m³

0.038 g/mL

Explanation:

Volume of a cube is the side length cubed.

V = s³

Given s = 0.65 m:

V = (0.65 m)³

V ≈ 0.275 m³

The mass is 10.5 kg.  The density is the mass divided by volume:

ρ = (10.5 kg) / (0.275 m³)

ρ ≈ 38 kg/m³

Or:

ρ ≈ 0.038 g/mL

4 0
3 years ago
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