The final pressure of the gas in the container is 4 atm
From the question given above, the following data were obtained:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 300 K
Initial pressure (P₁) = 1 atm
Final temperature (T₂) = 600 K
Final volume (V₂) = 2 L
<h3>Final pressure (P₂) =?</h3>
- Using the combine gas equation, we can obtain the final pressure of the gas as illustrated below:
Cross multiply
300 × 2 × P₂ = 4 × 600
600 × P₂ = 2400
Divide both side by 600
<h3>P₂ = 4 atm</h3>
Therefore, the final pressure of gas is 4 atm.
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Answer:
The value of Kc is 660 (Option E) is correct
Explanation:
Step 1: Data given
Kp = 27
Temperature = 25.0 °C
Step 2: The balanced equation
2 NO(g) + Br2(g) ⇄ 2 NOBr(g)
Step 3: Calculate Kc
Kp = Kc * (RT)^Δn
⇒ with Kp = 27
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 L*atm/mol*K
⇒ with T = The temperature = 25 °C = 298 K
⇒ Δn = the difference in moles = -1
27 = Kc * (0.08206*298)^-1
Kc = 660
The value of Kc is 660 (Option E) is correct
Answer:
why did you post a link to brainly when we are on brainly already??????
Explanation:
This segment is called a gene
Sodium phosphide is the inorganic compound with the formula Na3P.
