Question

Which of the following families on the periodic table is likely to take on 2 electrons?. . . family 2. family 12. family 16. family 18

Answer 1

Answer: Family 16 is most likely to accept 2 electrons.

Explanation:

Family 16 has the electronic configuration $ns^{2} np^{4}$. As to attain stability the p orbital will readily accept 2 electrons.

Therefore, family 16 is most likely to accept 2 electrons. Family 16 is also known as chalcogens.

Whereas, family 2 has the electronic configuration $(n-1)s^{2} ns^{2}$. As the s orbital is completely filled  so there is no need to accept 2 electrons.

Family 12, and family 18 has the electronic configuration $[Ar] nd^{10} ns^{2}$ and $[He]ns^{2} np^{6}$ respectively.

Both family 12 and 18 has completely filled orbitals so it will not accept any electrons.

Answer 2

If we say the words "take on 2 electrons" we mean to find the family that could accept 2 more electrons to satisfy the Octet Rule. Most of the elements that accept electrons are nonmetals. From the given above, the family to which this type is found is family 16.