All categories

3 years ago

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

1 answer:

6 0

$C_{m}=\frac{m}{MV}=\frac{73,5g}{98\frac{g}{mol}*3L}=0,25M\\\\
C_{1}V_{1}=C_{2}V_{2}\\\\
0,25M*3L=0,18M*V_{2}\\\\
V_{2}=\frac{0,25M*3L}{0,18M}\approx 4,17L\\\\
4,17L-3L=1,17L$

You might be interested in

Help! The question is in the picture

Ronch [10]

Answer:

little l big l big l little l

Explanation:

can you help me Complete the following sentence: After we explained why we needed her in the play, she and joined our rehearsal A quaffed B. acquiesced C vengeance D. wreaked

4 0

2 years ago

Give an<br> example of when a plant or animal might<br> use energy they have stored.

olasank [31]

Answer:

hunting for other animals or when they are really hungry

Explanation:

8 0

2 years ago

For the reaction: 4PH3(g) → P4(g) + 6H2(g) about 0.065 mol/s of PH3 is consumed in a 5.0 L flask. What are the rates of producti

hoa [83]

Answer: The rates of production of $P_4$ is $3.25\times 10^{-3}$ mol/Ls and $H_2$ is 0.0195 mol/Ls.

Explanation:

$4PH_3(g)\rightarrow P_4(g)+6H_2(g)$

Rate with respect to reactants is shown by negative sign as the reactants are decreasing with time and Rate with respect to products is shown by positive sign as the products are increasing with time.

Rate of the reaction= $-\frac{1}{4}\frac{[d[PH_3]}{dt}=\frac{[d[P_4]}{dt}=\frac{1}{6}\frac{[d[H_2]}{dt}$

Rate of decomposition of $PH_3=\frac{0.065 mol/s}{5.0L}=0.013mol/Ls$

Rate of production of $P_4=\frac{1}{4}\times {\text{rate of decomposition of}} PH_3=\frac{1}{4}\times 0.013=3.25\times 10^{-3}mol/Ls$

Rate of production of $H_2=\frac{6}{4}\times {\text {rate of decomposition of}} PH_3=\frac{6}{4}\times 0.013=0.0195mol/Ls$

7 0

3 years ago

Read 2 more answers

Which reaction is endothermic?

Naily [24]

The second equation is endothermic. the energy is listed in the reactants side. if it was a product it is exothermic. also the H value is negative exothermic positive endothermic

3 0

3 years ago

Read 2 more answers

A balloon contains 0.158 mol of gas and has a volume of 2.46 l. if an additional 0.113 mol of gas is added to the balloon (at th

MissTica

It should be something like that...see if u understand

4 0

2 years ago

Read 2 more answers