Answer:
little l big l big l little l
Explanation:
can you help me Complete the following sentence: After we explained why we needed her in the play, she and joined our rehearsal A quaffed B. acquiesced C vengeance D. wreaked
Answer:
hunting for other animals or when they are really hungry
Explanation:
Answer: The rates of production of
is
mol/Ls and
is 0.0195 mol/Ls.
Explanation:

Rate with respect to reactants is shown by negative sign as the reactants are decreasing with time and Rate with respect to products is shown by positive sign as the products are increasing with time.
Rate of the reaction=![-\frac{1}{4}\frac{[d[PH_3]}{dt}=\frac{[d[P_4]}{dt}=\frac{1}{6}\frac{[d[H_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5Bd%5BPH_3%5D%7D%7Bdt%7D%3D%5Cfrac%7B%5Bd%5BP_4%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7B%5Bd%5BH_2%5D%7D%7Bdt%7D)
Rate of decomposition of 
Rate of production of 
Rate of production of 
The second equation is endothermic. the energy is listed in the reactants side. if it was a product it is exothermic. also the H value is negative exothermic positive endothermic
It should be something like that...see if u understand