A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

1 answer:

6 0

$C_{m}=\frac{m}{MV}=\frac{73,5g}{98\frac{g}{mol}*3L}=0,25M\\\\
C_{1}V_{1}=C_{2}V_{2}\\\\
0,25M*3L=0,18M*V_{2}\\\\
V_{2}=\frac{0,25M*3L}{0,18M}\approx 4,17L\\\\
4,17L-3L=1,17L$

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