Question

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Answer 1

$C_{m}=\frac{m}{MV}=\frac{73,5g}{98\frac{g}{mol}*3L}=0,25M\\\\ C_{1}V_{1}=C_{2}V_{2}\\\\ 0,25M*3L=0,18M*V_{2}\\\\ V_{2}=\frac{0,25M*3L}{0,18M}\approx 4,17L\\\\ 4,17L-3L=1,17L$