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My name is Ann [436]
2 years ago
8

Measure and record the masses of all metal strips you set out in front of the test tubes

Chemistry
1 answer:
jeka942 years ago
3 0

Magnesium ribbon dissolves in zinc nitrate and copper nitrate solutions.

Even though the question is incomplete and refers to your practical work, however, I will try to help you as much as I can.

Metals dissolves in solutions of other metals that are lower than them in the electrochemical series. Hence, copper strip will show no change in magnesium nitrate or zinc nitrate solution. A zinc strip will not show any change in magnesium nitrate or zinc nitrate.

However, a magnesium ribbon will dissolve very quickly in zinc nitrate and copper nitrate solutions.

Learn more: brainly.com/question/14396802

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A sample of pure NH4HS is placed in a sealed 2.0-L container and heated to 550 K at which the equilibrium constant is 3.5 x 10-3
Zolol [24]

Answer:

The mass of NH_{3} in the container is 2.074 gram

Explanation:

Given:

Volume of NH_{4} HS    V = 2 lit

Equilibrium constant k _{eq} = 3.5 \times 10^{-3}

The reaction in which NH_{3} is produced

  NH_{4} HS ⇄ NH_{3} + H_{2}S

Here equal moles of NH_{3} and H_{2}S is formed.

From the formula of equilibrium constant,

  k_{eq} = (NH_{3})(H_{2}S )

   x^{2} = 3.5 \times 10^{-3}

     x = 0.061 M

Above value shows,

   NH_{3} = 0.061 \frac{moles}{L}

So in 2 L no. moles of NH_{3} = 0.061 \times 2 = 0.122 moles.

So mass of 0.122 mole of NH_{3} is = 0.122 \times 17 = 2.074 g

Therefore, the mass of NH_{3} in the container is 2.074 gram

8 0
3 years ago
How much heat is required to raise the temperature of 65.8 grams of water from 31.5ºC to 46.9ºC?
vodomira [7]

Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J

Explanation:

1) Data:

Water ⇒ C = 1 cal/g°C

m = 65.8 g

Ti = 31.5°C

Tf = 36.9°C

Heat, Q = ?

2) Formula:

Q = mCΔT

3) Calculations:

Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal

4) You can convert from calories to Joules using the conversion factor:

1 cal = 4.18 J

⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J

3 0
3 years ago
Calculate the number of moles<br> 41.0 g of Ca(NO3)2 <br> 1.48 g of Ca(OH)2 <br> 3.40 g of CaSO4
Lemur [1.5K]
First. moles is just a label for a number of things. just like a dozen = 12, a gross = 144, a mole = 6022 with another 20 zeros after the 2

next

moles = mass / molecular weight.

molecular weight = sum of atomic mass from the periodic table

atomic mass MnO2 = atomic mass Mn + 2 x atomic mass O
= 54.94 + 2 x 16 = 86.94 g/mole

so moles MnO2 = 98.0 grams / (86.94 g/mole) = 1.13 moles

notice that I only gave 3 digits? that because of sig figs read the link below if you don't understand....

mw C5H12 = 5 x 12 + 12 x 1 = 72 g/mole

so moles C5H12 = 12.0 g / 72.0 g/mole = 0.167 moles

mw XeF6 = 131.3+ 6 x 19.00 = 245.3

so moles XeF6 = 100 g / 245.3 g/mole = 0.4077 moles

I've also provided a link to a periodic table. if you need atomic weights click on any element and it will give you the
details.
8 0
3 years ago
Which of these lab safety procedures is INCORRECT?
Ksju [112]

Answer:

D

Explanation:

D is not necessary to follow lab safety in Laboratory

6 0
3 years ago
What happens to an ionic compound when it is dissolved in water?
damaskus [11]

Answer:

c

Explanation:

because the ion are Mobil which mean they are free not combined and carry a charge but when they are combined/ fixed in position they can't carry a charge so therefore can't conduct electricity  :)

8 0
3 years ago
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