Help Please!!!!!!
1 answer:
Answer:
centre = (2, - 1), radius = 6
Step-by-step explanation:
Rearrange the equation by placing the x and y terms together and adding 31 to both sides
Given
x² + y² - 4x + 2y - 31 = 0, then
x² - 4x + y² + 2y = 31
Use the method of completing the square
add ( half the coefficient of the x/y term )² to both sides
x² + 2(- 2)x + 4 + y² + 2(1)y + 1 = 31 + 4 + 1
(x - 2)² + (y + 1)² = 36
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r the radius
compare to (x - 2)² + (y + 1)² = 36, then
centre = (2, - 1) and r = = 6
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<h2>Explanation:</h2>In this exercise, <em>we have the following points:</em>
And <em>the following linear equations:</em>
When plotting these graphs, we find the following facts:
<h3>For (1):</h3>We see the graph in the first figure below. The graph only passes through the point (0, 8)
<h3>For (2):</h3>This is the second graph below. The graph passes neither through point (0, 8) nor (6, 4)
<h3>For (3):</h3>This is the third graph below. The graph passes neither through point (0, 8) nor (6, 4)
<h3>For (4):</h3>This is the fourth graph below. The graph only passes through the point (0, 8)
So, <em>there is no any equation of the line that passes through the points (0.8) and (6.4) at the same time.</em>
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<h2>Learn more:</h2>About lines: brainly.com/question/12169569
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