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nekit [7.7K]
3 years ago
5

A refrigerator is sold at $ 10525 at a profit of $ 925. What was the Cost Price of the refrigerator?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0
The price of the refrigerator was $9600
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9+m/3=2help me please
Verizon [17]

Answer:

m = -21

Step-by-step explanation:

9+m/3=2

1. Subtract 9 from both sides

9 - 9 + m/3 = 2 - 9

m/3 = -7

2. Multiply both sides by 3

3 (m/3) = -7 (3)

m = -21

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2 years ago
Please help out need it​
juin [17]

Answer:

at the answer is about 5.29

Step-by-step explanation:

to do this u need the pythagorean theorem.

a squared+ b squared=c squared

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8 0
3 years ago
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Write the equation of the line that passes through the points (−7,5) and (-7,-8).
Viefleur [7K]

Answer:

x = -7

Step-by-step explanation:

First we find the slope using

m = ( y2-y1)/(x2-x1)

   = ( -8 - 5)/( -7 - -7)

   = (-8-5)/(-7+7)

   = -13/0

This means the slope is undefined and the line is vertical

Vertical lines are in the form

x= constant and the constant is the x value of the points

x = -7

3 0
3 years ago
Are these right?!?! Cannot fail
jolli1 [7]
The first one is correct but I don’t know about the second one
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3 years ago
Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 6.9 per year. a. Find t
VLD [36.1K]

Answer:

a) 9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b) 4.284 years are expected to have 4 ​hurricanes.

c) The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

6.9 per year.

This means that \mu = 6.9

a. Find the probability​ that, in a​ year, there will be 4 hurricanes.

This is P(X = 4).

So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-6.9}*(6.9)^{4}}{(4)!}

P(X = 4) = 0.0952

9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b. In a 45​-year ​period, how many years are expected to have 4 ​hurricanes?

For each year, the probability is 0.0952.

Multiplying by 45

45*0.0952 = 4.284.

4.284 years are expected to have 4 ​hurricanes.

c. How does the result from part​ (b) compare to a recent period of 45 years in which 4 years had 4 ​hurricanes? Does the Poisson distribution work well​ here?

The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

5 0
3 years ago
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