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3 years ago

A rectangle is enlarged by a factor of 6.

Mathematics

2 answers:

Dmitrij [34]3 years ago

8 0

Answer:

its 720

Step-by-step explanation:

i took the test i don't understand the math behind it but i got it right i guess it would be 20 X 6 = 120 then X that by 6 to get 720

anastassius [24]3 years ago

3 0

Answer:

6 × 20

120 in^2

Step-by-step explanation:

in order to find the area of the enlarged rectangle, you can multiply the area of the rectangle by the factor of the rectangle that is enlarged.

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BRAINLIEST!!! 11. Solve the inequality and graph the solution on a number line.

PilotLPTM [1.2K]

Answer:

y≤-1/3 (fraction)

And on the number line it will start from -1/3 (-0.333) and go less than -1/3 ( to the left, and it will be shaded

Step-by-step explanation:

First we expand the brackets, making it -15y+12≥17

Then we move 12 to the other side, making it negative, -15y≥17-12

Simplify, -15y≥5

Then we divide on both sides to isolate y, flipping the greater than sign to less than because when you divide or multiply by a negative number, the sign flips. y≤5/-15

Then we simplify by dividing the fraction by 5, making it -1/3. y≤-1/3

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3 years ago

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A model of a tree is made using a scale of 1 inch = 25 feet. What is the height of the actual tree if the height of the model is

Anni [7]

The tree is 109.375 feet tall

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3 years ago

If the circumference of a circle is 120 inches and M angle B equals 18° then what is the length of arc AC

Andru [333]

Answer:

For a circle of radius R, the circumference is:

C = 2*pi*R

where pi = 3.14

And if we have an arc defined by an angle θ, the length of the arc is:

A = (θ/360°)*2*pi*R

Here we can not see the image, then i assume that B is the angle that defines the arc AC.

Now we know that the circumference is 120 in, then:

2*pi*R = 120in

Then the length of the arc is:

A = (θ/360°)*120 in

Then if the angle is 18°, we have:

A = (18°/360)*120 in = 6in

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3 years ago

I just need to know if it’s a b c or d please and thx u

vagabundo [1.1K]

Answer:

i think its B

Step-by-step explanation:

sorry if its wrong have a good day/night ;)

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3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

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3 years ago

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