Answer:
brueh what im confused
Step-by-step explanation:
I'll just take the points thanks XD
By definition, a polynomial is an expression with more than one term. That is a monomial. We have names for 2-termed polynomials (binomials) and 3-termed polynomials (trinomials), but that's where the naming stops and they all are called polynomials after that. Our degree is the same as the highest exponent. So our degree is a fifth degree. The leading coefficient is the number that starts out the whole polynomial AS LONG AS IT IS IN STANDARD FORM. If our polynomial started with the -4x^4, our leading coefficient would NOT be -4 since the highest degree'd term will always come first in standard form. Your choice for your answer is the first one given. Degree: 5 Leading Coefficient: -13.
We need to compute the exact number of days of the loan.
Given:
Loan: 1,870
rate: 11%
term: Oct. 5 to Jan 16.
Oct 5-Oct 31: 26 days
Nov: 30 days
Dec: 31 days
Jan 16: 16 days.
total number of days: 103 days.
Interest = Principal * rate * term
Interest = 1870 * 0.11 * 103/365
Interest = 58.05
Given:
Promissory note $5,380
rate 6.2%
term: July 15 to Dec. 28
July 15 - 31 = 16 days
August: 31 days
September: 30 days
October: 31 days:
November: 30 days
December: 28 days
Total number of days is 166 days
Interest = Principal * rate * term
Interest = 5,380 * 0.062 * 166/365
Interest = 151.70
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
