A ray is a defined term because it

Mathematics

2 answers:

Korolek [52]3 years ago

5 0

The answer is B:) Are you in the school Laurel Springs?

m_a_m_a [10]3 years ago

3 0

Answer:

Option D is correct.

Step-by-step explanation:

Given that

A ray is a defined term we have to give the reason of the above statement.

A ray is a line or a part of a line that has one endpoint which we defined and other goes on infinitely in only one direction.

One of the example is a sun's ray of light in space. Light from the sun originates and travels from the sun, and its path extends infinitely.\

Hence, we say that "A ray is a defined term because it travels forever in one direction"

Option D is correct.

You might be interested in

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$