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vesna_86 [32]
3 years ago
11

I need help. ASAP! Look at the picture below. (6)

Chemistry
1 answer:
Mice21 [21]3 years ago
4 0
It's B
because ionic molecules are not soluble in oil
polar molecules are soluble in water
nonpolar molecules are not soluble in water

and metals are not soluble neither in water nor in oil
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What is the morality of a solution made with 0.88 moles of KCl and 2.0 L of water?
Anarel [89]

Answer:

M=0.44M

Explanation:

Hello,

In this case, the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

M=\frac{n_{solute}}{V_{solution}}

In this case, the solute is the KCl (potassium chloride) and the solution is made up of both water and KCl. Moreover, since during this type of dissolution processes, the volume of the solution is not significantly affected by the addition of the solute, the resulting molarity is:

M=\frac{0.88mol}{2.0L}\\ \\M=0.44M

Best regards.

4 0
3 years ago
A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?
makkiz [27]

Answer:

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bittuly/3a8Nt8

Explanation:

6 0
3 years ago
Hi everyone, I'm really stuck on a question for my uni assignment, i just dont understand chemistry at all, i was wondering if a
sdas [7]
<h3>Answer : 2C + 3H2 -> C2H6</h3>

<h3>Step and explanation</h3>

Condition : graphite + hydrogen gas

Chemical formula : C + H2

Reaction formula :

C + H2 -> C2H6

#First, you see the number of atom

•Product

C = 1

H = 2

•Reactant

C = 2

H = 6

<em>#</em><em>N</em><em>o</em><em>t</em><em>e</em><em> </em><em>that</em><em>,</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>chemical</em><em> </em><em>reaction</em><em> </em><em>both</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>each</em><em> </em><em>atom</em><em> </em><em>in</em><em> </em><em>product</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>equal</em><em> </em><em>in</em><em> </em><em>reactant</em><em> </em><em>so</em><em>,</em><em> </em><em>you</em><em> </em><em>think</em><em> </em><em>what</em><em> </em><em>number</em><em> </em><em>you</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>put</em><em> </em><em>Infront</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>chemical</em><em> </em><em>formula</em><em> </em><em>so</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>atom</em><em> </em><em>equal</em>

2C + 3H2 -> C2H6

#Now check again

•Product

C = 2

H = 6

•Reactant

C = 2

H6

#Now, its equal. The bold one is the balance chemical reaction

<h3>Note (just incase u dont know)</h3>

Reactant -> product (the thing you get after reaction)

7 0
3 years ago
If 10.0 moles of sulfur dioxide react with excess chlorine gas, what is the theoretical yield (in grams) of CI2O produced?
xz_007 [3.2K]

Answer:

869 g Cl₂O

Explanation:

To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).

1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)

Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol

Molar Mass (Cl₂O): 86.904 g/mol

10.0 moles SO₂         1 mole Cl₂O            86.904 g
------------------------  x  ----------------------  x  ------------------  = 869 g Cl₂O
                                    1 mole SO₂              1 mole

6 0
2 years ago
Compound A is an alkene that was treated with ozone to yield only (CH3CH2CH2)2C=O. Draw the major product that is expected when
DochEvi [55]

Answer:

2,2,3,3-tetrapropyloxirane

Explanation:

In this case, we have to know first the alkene that will react with the peroxyacid. So:

<u>What do we know about the unknown alkene? </u>

We know the product of the ozonolysis reaction (see figure 1). This reaction is an <u>oxidative rupture reaction</u>. Therefore, the double bond will be broken and we have to replace the carbons on each side of the double bond by oxygens. If (CH_3CH_2CH_2)_2C=O is the only product we will have a symmetric molecule in this case 4,5-dipropyloct-4-ene.

<u>What is the product with the peroxyacid?</u>

This compound in the presence of alkenes will produce <u>peroxides.</u> Therefore we have to put a peroxide group in the carbons where the double bond was placed. So, we will have as product <u>2,2,3,3-tetrapropyloxirane.</u> (see figure 2)

3 0
3 years ago
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