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2 years ago

I need help. ASAP! Look at the picture below. (6)

Chemistry

1 answer:

Mice21 [21]2 years ago

4 0

It's B
because ionic molecules are not soluble in oil
polar molecules are soluble in water
nonpolar molecules are not soluble in water

and metals are not soluble neither in water nor in oil

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Which set of coefficients correctly balances the following chemical equation?__ AgNO3 + ___ MgCl2 --> ___ AgCl + ___ Mg(NO3)2

melisa1 [442]

It is C 2 1 2 1

You have to 1st balance the nitrates then balance the silvers to get the coefficients

4 0

2 years ago

Read 2 more answers

A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 30.0 g carbon and 40.0 g oxygen. Another sam

mote1985 [20]

Answer:

16.933g approximately 17.0 grams

Explanation:

From the simple promotions and given the same compound ascorbic acid (vitamin C)

In the laboratory synthesised ascorbic acid

Mass of carbon = 30.0g

Mas of Oxygen = 40.0g

That is the mass of Oxygen per unit mass of Carbon

Per gram of Carbon we have

(30.0g Carbon)÷30 combines with (40.0g of Oxygen)÷30

That is 4/3g of Oxygen per gram of Carbon

Hence the mass of Oxygen compound that combines with 12.7g of Carbonin natural occurring ascorbic acid (vitamin C) is = 4/3×12.7 = 16.933g approximately 17.0g

8 0

2 years ago

Identify what the conjugate acid/base would be. FOR H3PO4?

natali 33 [55]

Phosphoric acid. Also known as orthophosphoric acid in or phosphoric(V) acid, is a weak acid with the chemical formula H3PO4. The pure compound is a colorless solid.

6 0

2 years ago

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At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration

wlad13 [49]

Answer:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.03901 mol/liter

[Cl₂O] = 0.02351 mol/liter

Explanation:

1. Chemical reaction:

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

2. Initial concentrations:

i) 1.3 g H₂O

Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol

Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol

Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

3. ICE (Initial, Change, Equilibrium) table

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

I 0.0481 0.0326 0

C -x -x +x

E 0.0481-x 0.0326-x x

4. Equilibrium expression

$K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}$

$0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}$

5. Solve:

$x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0$

Use the quadatic formula:

$x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}$

The positive result is x = 0.00909

Thus the concentrations are:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter

[Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

3 0

2 years ago

How many moles at STP would take up 44.8 liters?

Tom [10]

Answer:

n = 2 mol

Explanation:

Given data:

Pressure = standard = 1 atm

Temperature = standard = 273.15 K

Volume = 44.8 L

Number of moles = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

1 atm × 44.8 L = n × 0.0821 atm.L/ mol.K × 273.15 K

44.8 atm.L = n × 22.43 atm.L/ mol

n = 44.8 atm.L / 22.43 atm.L/ mol

n = 2 mol

4 0

2 years ago