Answer:
The cost of electricity for 100 W power bulb = $ 32.85
Cost of electricity for 0.025 W fluorescent bulb = $ 8.2125
Explanation:
Cost of electricity = $ 0.18 per KW-H
Time = 5 hour per day
Bulb power = 100 W = 0.1 KW
Fluorescent bulb power = 25 W = 0.025 KW
(a) Cost of electricity for 100 W power bulb
0.1 × 5 × 365 × 0.18 = $ 32.85
(b) Cost of electricity for 0.025 W fluorescent bulb
0.025 × 5 × 365 × 0.18 = $ 8.2125
Therefore the cost of electricity for 100 W power bulb = $ 32.85
Cost of electricity for 0.025 W fluorescent bulb = $ 8.2125
<span>will they contain the same number of protons as electrons. By the meaning, an "ion" is an electrically charged particle produced by either removing electrons from the neutral atom to give a positive ion or adding electrons to a neutral atom to give a negative" ion".
hope i helped :)
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The question is incomplete, here is the complete question:
Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in 
The image is attached below.
<u>Answer:</u> The density of CsI is 
<u>Explanation:</u>
To calculate the density of metal, we use the equation:
where,
= density
Z = number of atom in unit cell = 2 (BCC)
M = atomic mass of CsI = 259.8 g/mol
= Avogadro's number = 
a = edge length of unit cell = 
(Conversion factor: 
)
Putting values in above equation, we get:
Hence, the density of CsI is
Answer:
1. Protons
2. Electrons
3. Neutrons
4. Protons and neutrons
5. Electrons
Explanation:
The protons are the only positive sub-atomic particles and the have a charge of +1.
The Electrons are the only negative subatomic particles and they have a charge of -1
Neutrons do not have any charge but they have the same mass as the protons
The nucleus of an atom is where most of the atomic masses are concentrated and it houses the neutrons and protons
The electrons reside outside the nucleus and they have a much more lesser mass compared to the neutrons and protons
Answer:
A. Along warm-water currents from warmer regions to colder regions
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Explanation:
