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3 years ago

Which half reaction is most easily reduced?

2 answers:

8 0

Thank you for posting your question here at brainly. Among the choices provided the answer should be Br2 + 2e− → 2Br− = 1.07 V.

I hope the answer will help. Feel free to ask more question.

GuDViN [60]3 years ago

7 0

Answer;

Br2 + 2e− → 2Br− = 1.07 V

Explanation;

-Oxidation is the loss of electrons while reduction is the gaining of electrons. Reducing agent undergoes oxidation while oxidizing agent undergoes reduction.

- In the above question, bromine is the strongest reducing agent because it has the highest positive value of an emf. Zinc ion on the other hand is the strongest oxidizing agent since it has the highest negative emf.

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Which components of a galaxy move in circular patterns or revolve around a star?

Novosadov [1.4K]

Answer:

Explanation: hoped this helped!!!

8 0

3 years ago

Potassium metal and chlorine gas combine in a reaction to produce an ionic compound. What is the correct balanced equation for t

Alisiya [41]

Answer:

2K (s) + Cl₂ (g) ⇒ 2KCl (s)

Explanation:

Potassium and chlorine gas combine to form potassium chloride which is an ionic compound. The reaction is a type of combination reaction in which chlorine is being added to the metal, potassium.

Potassium reacts violently with the chlorine which is yellowish green in color to produce white solid of potassium chloride.

The balanced reaction is shown below as:

2K (s) + Cl₂ (g) ⇒ 2KCl (s)

6 0

3 years ago

What are you suppose to do for number 8?

Nadya [2.5K]

Answer:

See the images below

Step-by-step explanation:

To draw a dot diagram of an atom, you locate the element in the Periodic Table and figure out how many valence electrons it has. Then you distribute the electrons as dots around the atom,

a. Silicon.

Si is in Group 14, so it has four valence electrons.

b. Xenon

Xenon is in Group 18, so it has eight valence electrons. We group them as four pairs around the xenon atom.

c. Calcium

Calcium is in Group 2, so it has two valence electrons. They are in a single subshell, so we write them as a pair on the calcium atom.

d. Water

Oxygen is in Group 16, so it has six valence electrons. The hydrogen atoms each contribute one electron, so there are eight valence electrons.

Chemists often use a dash to represent a pair of electrons in a bond.

3 0

3 years ago

Dihydrogen dioxide decomposes into water and oxygen gas. Calculate the amounts requested if 1.34 moles of dihydrogen dioxide rea

a_sh-v [17]

Answers:

a. Moles of oxygen formed: 0.670 mol

b. Moles of water formed: 1.34 mol

c. Mass of water formed: 24.1 g

d. Mass of oxygen formed: 21.4 g

Explanation:

Dihdyrogen dioxide is the chemical name for a compound made of two hydrogen atoms and two oxide atoms, i.e. H₂O₂, which is also known as hydrogen peroxide or oxygenated water.

The decomposition reaction of dihydrogen dioxide into water and oxygen gas is represented by the balanced chemical equation:

$2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g)$

The mole ratios derived from that balanced chemical equation are:

2 mol H₂O₂ : 2 mol H₂O : 1 mol O₂

a. Moles of oxygen formed

Set the proportion using the theoretical mole ratio of H₂O₂ to O₂ and the amount of moles of dyhydrogen dioxide that react:

$2\text{ mol }H_2O_2/1\text{ mol }O_2=1.34\text{ mol }H_2O_2/x$

When you solve for x, you get:

x = 1.34 mol H₂O₂ × 1 mol O₂ / 2 mol H₂O₂ = 0.670 mol O₂

b. Moles of water formed

Set the proportion using the theoretical mole ratio of H₂O₂ to H₂O and the amount of moles of dyhydrogen dioxide that react:

$2\text{ mol }H_2O_2/2\text{ mol }H_2O=1.34\text{ mol }H_2O_2/x$

When you solve for x, you get:

x = 1.34 mol H₂O₂ × 2 mol H₂O / 2 mol H₂O₂ = 1.34 mol H₂O

c. Mass of water formed

Using the number of moles of water calculated in the part b., you calculate the mass of water formed, in grams, using the molar mass of water:

Molar mass of water = 18.015 g/mol

Number of moles = mass in grams / molar mass

⇒ mass in grams = number of moles × molar mass

⇒ mass in grams = 1.34 mol × 18.015 g/mol = 24.1 g

d. Mass of oxygen formed

Using the number of moles of oxygen determined in the part a., you calculate the mass in grams using the molar mass of O₂.

Molar mass of O₂ = 32.00 g/mol

mass = molar mass × number of moles

mass = 32.00 g/mol × 0.670 mol = 21.4 g.

5 0

3 years ago

Scientific investigations must be well __________ to be sure the data collected will help answer the scientist's question

Shalnov [3]

Answer:

The answer is relevant.

6 0

3 years ago