Suspensions
Explanation:
Suspensions are heterogeneous mixtures that contains large particles that can settle out or be filtered.
- Suspensions are mixtures of small insoluble particles of a solid in a liquid or gas.
- Examples are:
- powdered chalk in water
- muddy water
- harmattan
The particles in suspension can settle on standing
Learn more:
Suspension brainly.com/question/1557970
heterogeneous mixture brainly.com/question/1446244
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Answer: D) sweat requires a lot of thermal energy to be absorbed to evaporate
Explanation:
i took the test
The mass of the liquid is 4.8 kg.
6.4 L = 6400 mL
Mass = 6400 mL × (0.70 g/1 mL) = 4500 g = 4.8 kg
Answer:
concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 0.0248 = 2.48 ×10⁻² M
concentration of
= 0.4442 M
Explanation:
Equation for the reaction:
⇄
+ 
Concentration of
=
= 0.469
For our ICE Table; we have:
⇄
+ 
Initial 0.469 0 0
Change - 2x +2x +x
Equilibrium (0.469-2x) 2x x
K = ![\frac{[CO]^2[O]}{[CO_2]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5D%5E2%5BO%5D%7D%7B%5BCO_2%5D%5E2%7D)
K = ![\frac{[2x]^2[x]}{[0.469-2x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2x%5D%5E2%5Bx%5D%7D%7B%5B0.469-2x%5D%5E2%7D)

Since the value pf K is very small, only little small of reactant goes into product; so (0.469-2x)² = (0.469)²




![x=\sqrt[3]{1.9929*10^{-6}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B1.9929%2A10%5E%7B-6%7D%7D)
x = 0.0124
∴ at equilibrium; concentration of
= 0.0124 = 12.4 ×10⁻³ M
concentration of
= 2x = 2 ( 0.0124)
= 0.0248
= 2.48 ×10⁻² M
concentration of
= 0.469-2x
= 0.469-2(0.0124)
= 0.469 - 0.0248
= 0.4442 M