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Viktor [21]
3 years ago
6

How Do I Multiply? Please Answer Quickly!!!​

Mathematics
2 answers:
Ivanshal [37]3 years ago
4 0

Answer: say for instance 2x11

you would multiply 2x1 =2

Then multiply 2 times the other 1 which would equal 22.

Step-by-step explanation:

Yuki888 [10]3 years ago
3 0

Answer:

You just add.

3x3= 9

3+3+3=9

Step-by-step explanation:

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The Webb Institute offers free college tuition for those majoring in engineering. For fall 2015, 2 out of the 24 students who en
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Solve for x= ax2 + b = c
alekssr [168]

Answer:

x = ± \sqrt{\frac{c-b}{a} }

Step-by-step explanation:

Given

ax² + b = c ( subtract b from both sides )

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x² = \frac{c-b}{a} ( take the square root of both sides )

x = ± \sqrt{\frac{c-b}{a} }

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2 years ago
Find both unit rates. 1435 points scored in 25 games + Brainliest!!
kozerog [31]
In this case, the unit is points (1,435) and the time is games (25). So, we divide the unit by the rate to get the unit rate of 57.5.

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5 0
3 years ago
Use the given degree of confidence and sample data to construct interval for the population proportion. Of 369 randomly selected
Alexxx [7]

Answer:

e)  (3.77%, 8.70%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given random sample size 'n' = 369

Sample proportion

                              p = \frac{x}{n} = \frac{23}{369} = 0.0623

95% confidence intervals are determined by

(p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })

(0.0623 - 1.96 \sqrt{\frac{0.0623(1-0.0623)}{369} } , 0.0623 + 1.96\sqrt{\frac{0.0623(1-0.0623)}{369} })

(0.0623 - 0.0246 , 0.0623 + 0.0246)

(0.0383 , 0.0869)

(3.83% , 8.69%)

95% confidence interval for the percentage of all medical students who plan to work in a rural community

(3.83% , 8.69%)

<u>Step(ii):-</u>

Given 43% of those polled blamed of companies the most for the recent increase in gasoline prices

sample proportion 'p' = 0.43

Given Margin of error (M.E) = 0.024

95% confidence intervals are determined by

(p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} })

(0.43 - 0.024 } , 0.43 +0.024 )

(0.406 , 0.454)

<u>Final answer</u>:-

95% confidence level for the population proportion who blame oil companies for the recent increase in gasoline prices

(0.406 , 0.454)

6 0
3 years ago
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