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Hunter-Best [27]
3 years ago
11

You are making a 0.2M solution of sodium acetate in the lab. Sodium acetate has a molecular mass of 82.03 g/mol. How many g of s

odium acetate will you use if you are making 500mL of the solution
Chemistry
1 answer:
lyudmila [28]3 years ago
7 0

Answer: The answer can be found on CHEG

Explanation:

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That if we don’t separate our selves hundreds and thousands of people will die but if we stay apart it will resolve sooner
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Who was the first person known to have used the terms genus and species when classifying organisms?
velikii [3]

C Linnaeus was the first person known to have used the terms genus and species when classifying organisms.

4 0
3 years ago
A flask with a volume of 250.0 mL contains air with a density of 1.164 g/L. What is the mass of the air contained in the flask?
satela [25.4K]

Answer:

convert 250.0 mL in Liters :250. 0 / 1000 = 0,25 LDensity = 1.240 g/LMass

Explanation:

6 0
2 years ago
Fill in the blanks with the correct term.
zzz [600]

Answer:

Fill in the blanks with the correct term.

a. a liquid that dissolves another substance.

b. a chemical that is dissolved.

c. a value used to describe the amount of one substance dissolved in another.

d. a liquid consisting of one substance dissolved in another.

Explanation:

a. A liquid that dissolves another substance is called the solvent.

b. A chemical that is dissolved solute.

c. A value used to describe the amount of one substance dissolved in another is called concentration.

d. A liquid consisting of one substance dissolved in another is called a solution.

4 0
3 years ago
2C4 H10 + 13O2 -→ 8CO2 + 10H2O If 356 moles of O2 are available to react, how many moles of CO2 will fom?
nlexa [21]

Answer:

Answer:

The mole ratio of C₄H₁₀ and CO₂ is 2 : 8, which  simplifies to 1 : 4.

Explanation:

The mole ratio is the relative proportion of the moles of products or reactants that participate in the reaction according to the chemical equation.

The chemical equation given is:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Once you check that the equation is balanced, you can set the mole ratios for all the reactants and products. The coefficients used in front of each reactant and product, in the balanced chemical equation, tells the mole ratios.

In this case, they are: 2 mol C₄H₁₀ :  13 mol O₂ : 8 mol CO₂ : 10 mol H₂O

Since you are asked about the mole ratio of C₄H₁₀ and CO₂ it is:

2 mol C₄H₁₀ : 8 mol CO₂ , which dividing by 2, simplifies to

1 mol C₄H₁₀ : 4 mol CO₂, or

1 : 2.

Explanation:

5 0
3 years ago
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