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juin [17]
3 years ago
10

Consider the balanced chemical reaction below and determine the percent yield for iron if 11.2 moles of Iron(III) oxide yielded

17.4 moles of iron
Fe2O3+3CO>2Fe+3CO2
Chemistry
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

The yield percent is 77.68%

Explanation:

Fe_{2}O_{3}+3CO\longrightarrow2Fe+3CO_{2}

1 mole of Fe_{2}O_{3} yields 2 moles of Fe.

So, 11.2 moles of Iron(III) oxide must yield 22.4 moles of Fe theoretically. This is according to the balanced equation.

Theoretical Yield = 22.4 moles of Fe

Experimental Yield = 17.4 moles of Fe

Yield\:Percentage=\frac{Experimental\:Yield}{Theoretical\:Yield}\times100\\\\Yield\:Percentage=\frac{17.4}{22.4}\times100=77.68\%

Therefore, the yield percent is 77.68%

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