Consider the balanced chemical reaction below and determine the percent yield for iron if 11.2 moles of Iron(III) oxide yielded
1 answer:
Answer:
The yield percent is 77.68%
Explanation:
1 mole of yields 2 moles of Fe.
So, 11.2 moles of Iron(III) oxide must yield 22.4 moles of Fe theoretically. This is according to the balanced equation.
Theoretical Yield = 22.4 moles of Fe
Experimental Yield = 17.4 moles of Fe
Therefore, the yield percent is 77.68%
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Answer:
Similarities: both state the mass of chemical species and they have the same numerical value
Differences: molecular mass refers to one single molecule and molar mass refers to one mole of a molecule
Explanation:
The molecular mass is the value of the mass of each molecule and it is measured in mass units (u). It is calculated adding the mass of each atom of the molecule.
The molar mass is the value of the mass of one mole of molecules, which means the mass of 6.022140857 × 10²³ molecules. The unit is g/mol.
For example, we can consider the methane molecule, which has the chemical formula of CH₄:
Molecular mass CH₄ = C mass + 4 x (H mass)
Molecular mass CH₄ = 12.01 + 4 x (1.01)
Molecular mass CH₄ = 16.05 u
Now to calculate the molar mass we multiply the value of the molecular mass by the Avogadro number and convert the units to g/mol:
Molar mass CH₄: 16.05 x x 6.022140857 × 10²³ mol⁻¹
Molecular mass CH₄ = 16.05 g / mol