Consider the balanced chemical reaction below and determine the percent yield for iron if 11.2 moles of Iron(III) oxide yielded
1 answer:
Answer:
The yield percent is 77.68%
Explanation:
1 mole of yields 2 moles of Fe.
So, 11.2 moles of Iron(III) oxide must yield 22.4 moles of Fe theoretically. This is according to the balanced equation.
Theoretical Yield = 22.4 moles of Fe
Experimental Yield = 17.4 moles of Fe
Therefore, the yield percent is 77.68%
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