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Travka [436]
4 years ago
12

What was the velocity of a dog that ran 50 meters in 15 seconds?

Physics
2 answers:
NARA [144]4 years ago
8 0

Answer:

velocity = 3.33 m/sec

Explanation:

<u>velocity = distance / time</u>

where

distance = 50 meters i

time = 15 seconds

plugin values into the formula

velocity =<u> 50 m </u>

                15 sec

velocity = 3.33 m/sec

solmaris [256]4 years ago
5 0

Answer:

5m/s

Explanation:

there are 3,600 seconds per hour so 5•3600 18,000 hours and 18 km/h

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If a truck weighs 195,000N what is the mass of the truck
Vsevolod [243]

Answer:

19500kg

Explanation:

If you divide 195000N by 10

8 0
3 years ago
A rocket experiences a 45,000 N force as it accelerates at 30 m/s/s. What is the mass of the rocket?
Gre4nikov [31]

Answer:

15,00kg

Explanation:

here's your solution

=> force = 45,000N

=> acceleration = 30m/s^2

=> mass = ?

=> Mass = force/acceleration

=> mass = 45,000/30

=> mass = 15,00kg

hope it helps

6 0
3 years ago
A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?
lapo4ka [179]
<h2>Answer: 12.24m/s</h2>

According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.

Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

V_{f}^{2}-V_{o}^{2}=2.a.d   (1)

Where:

V_{f} is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

V_{o} is the Initial Velocity, the value we want to find

a is the constant acceleration of the car (the negative sign means the car is decelerating)

d is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find V_{o}:

0-V_{o}^{2}=2(-5m/{s}^{2})(15m)    (2)

-V_{o}^{2}=-150{m}^{2}/{s}^{2}    (3)

Multiplying by -1 on both sides of the equation:

V_{o}^{2}=150{m}^{2}/{s}^{2}    (4)

V_{o}=\sqrt{150{m}^{2}/{s}^{2}}    (5)

Finally:

V_{o}=12.24m/s >>>This is the Initial velocity of the car

5 0
3 years ago
A baseball player slides into third base with an initial speed of 4.0 m/s . if the coefficient of kinetic friction between the p
satela [25.4K]
The work done by the friction force to stop the player is equal to his loss of kinetic energy:
W= \Delta K

The work done by the friction force is the magnitude of the force \mu m g times the distance covered by the player, d:
W= \mu mg d

The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):
\Delta K=K_i =  \frac{1}{2}mv^2

Substituting into the first equation, we get:
\mu m g d=  \frac{1}{2}mv^2
from which we find d, the distance covered by the player:
d= \frac{v^2}{2 \mu g}= \frac{(4.0 m/s)^2}{2 \cdot 0.4 \cdot 9.81 m/s^2}=2.04 m
4 0
3 years ago
nan moved 18m to the right and then another 22m to the right if the motion takes 20 seconds what is nans velocity
IrinaVladis [17]
Step 1: list known info

distance(change in position (Δx))= 18m+22m= 40m
time= 20 seconds

Step 2 :solve for velocity

velocity= Δx÷time
v= 40/20= 2m/s

Answer: the velocity is 2 meters per a second (m/s)


7 0
3 years ago
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