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2 years ago

14

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1 answer:

777dan777 [17]2 years ago

3 0

Newtons first law of motion.

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If you are given distance and a period of time what can you calculate

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If you are given distance and a period of time, you can calculate the speed. The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of its speed and direction of motion (e.g. 60 km/h to the north).

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3 years ago

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How are metal bridges built to cope with changes of temperature?

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2 years ago

The radius of a planet is 2400 km, and the acceleration due to gravity at its surface is 3.6 m/s2.

kiruha [24]

Answer:

$3.1\cdot10^{23}\:\mathrm{kg}$

Explanation:

We can use Newton's Universal Law of Gravitation to solve this problem:

$g_P=G\frac{m}{r^2}$ ., where $g_P$ is acceleration due to gravity at the planet's surface, $G$ is gravitational constant $6.67\cdot 10^{-11}$ , $m$ is the mass of the planet, and $r$ is the radius of the planet.

Since acceleration due to gravity is given as $m/s^2$ , our radius should be meters. Therefore, convert $2400$ kilometers to meters:

$2400\:\mathrm{km}=2,400,000\:\mathrm{m}$ .

Now plugging in our values, we get:

$3.6=6.67\cdot10^{-11}\frac{m}{(2,400,000)^2}$ ,

Solving for $m$ :

$m=\frac{2,400,000^2\cdot3.6}{6.67\cdot 10^{-11}},\\m=\fbox{$3.1\cdot10^{23}\:\mathrm{kg}$}$ .

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2 years ago

Why do bases make good household cleaners? a. They are not irritants c. They have low pH's b. They are not corrosive d. They rea

Dimas [21]

D. they react with oils and fats

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2 years ago

Given one mole of diamond vs one mole of graphite,

grandymaker [24]

Answer:

The pressure is $P= - 6.39*10^8Pa$

The temperature is $T =1218.63 K$

Explanation:

Generally Gibbs free energy is mathematically represented as

$G = E + PV -TS$

Where E is the enthalpy

PV is the pressure volume energy (i.e PV energy)

S is the entropy

T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

So at temperature of T = 300 K

$E + PV - TS = 0$

making P the subject

$P = \frac{TS-E}{V}$

Now substituting 300 K for T , 2900 J for E ,

$3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3$ for V and $2.38 J/K$ for S

$P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}$

$P= - 6.39*10^8Pa$

The negative sign signifies the direction of the pressure

Given that $P = 1*0^5Pa$

making T the subject

$T = \frac{PV+E}{S}$

Substituting into the equation

$T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}$

$T =1218.63 K$

7 0

3 years ago

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