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tester [92]
3 years ago
15

A 1.0 kg cart moving at 2.0 m/s collides with a stationary 2.0 kg cart.how fast do the two move together if they become stuck to

gether?

Physics
1 answer:
mafiozo [28]3 years ago
7 0
Hope it cleared your doubt.

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Not affected by acids a physical or chemical?
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physical because chemical always reacts

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The period of a pendulum may be decreased by
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The force of the pulley is 652 newtons. It accelerates at 53 m/s. How much does the object weigh. a 1230 grams b 1.230 gram c 12
RoseWind [281]

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d. 12.30 grams

Explanation:

Given the following data;

Force = 652 N

Acceleration = 53 m/s²

To find how much the object weigh, we would need to determine its mass;

Force = mass * acceleration

652 = mass * 53

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<em>Mass = 12.30 grams.</em>

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Proxima Centauri and the Sun are both main-sequence stars, but Proxima Centauri is a red dwarf and the Sun is a yellow dwarf. Ba
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Answer:

Yellow dwarfs are small, main sequence stars. The Sun is a yellow dwarf. A red dwarf is a small, cool, very faint, main sequence star whose surface temperature is under about 4,000 K. Red dwarfs are the most common type of star. Proxima Centauri is a red dwarf.

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(a) calculate earth's mass given the acceleration due to gravity at the north pole is 9.830 m/s2 and the radius of the earth is
kakasveta [241]

(a) The value of the gravitational acceleration is given by:

g=\frac{GM}{r^2}

where

G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M is the Earth's mass

r=6371 km=6.371 \cdot 10^6 m is the Earth's radius at the pole

If we use the value for g given by the problem, g=9.830 m/s^2, and we rearrange the equation above, we find the value of the Earth's mass:

M=\frac{gr^2}{G}=\frac{(9.830 m/s^2)(6.371 \cdot 10^6 m)^2}{6.67 \cdot 10^{-11} m^3 kg^{-1}s^{-2}}=5.982 \cdot 10^{24} kg

(b) The value we found for the Earth's mass is 5.982 \cdot 10^{24} kg, and we see that this value is slightly larger than the accepted value of 5.979 \cdot 10^{24} kg.

5 0
3 years ago
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