A busy chipmunk runs back and forth along a straight line of acorns that has been set out between his burrow and a nearby tree.
1 answer:
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Answer:
part (a)
Part (b)
Explanation:
Given,
- Mass of the larger disk =
- Mass of the smaller disk =
- Radius of the larger disk =
- Radius of the smaller disk =
- Mass of the block = M = 1.60 kg
Both the disks are welded together, therefore total moment of inertia of the both disks are the summation of the individual moment of inertia of the disks.
part (a)
Given that a block of mass m which is hanging with the smaller disk,
Let 'T' be 'a' be the tension in the string and acceleration of the block.
From the free body diagram of the smaller block,
From the pulley,
From the equation (1) and (2),
part (b)
Above expression for the acceleration of the block is only depended on the radius of the pulley.
Radius of the larger pulley =
Let be the acceleration of the block while connecting to the larger pulley.
The potential energy of the spring is 6.75 J
The elastic potential energy stored in the spring is given by the equation:
where;
k is the spring constant
x is the compression/stretching of the string
In this problem, we have the spring as follows:
k = 150 N/m is the spring constant
x = 0.3 m is the compression
Substituting in the equation, we get
Therefore. the elastic potential energy stored in the spring is 6.75J .
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