Answer:
e. 27 rho.
Explanation:
The density of an object, assumed constant, is defined as the relationship between the mass and the volume.
If the object is compressed in such a way that the diameter is reduced to 1/3, this means, that the radius will be reduced in the same proportion.
Now, if the mass remains the same (the compression can't change it) , the volume (assumed to be a perfect sphere) will be reduced also:
V₀ = 4/3*π*r³
Vf= 4/3*π*(r/3)³ = 4/3*π*(r³/27) = V₀/27
As the volume is in in the denominator of the expression for density, this means that the new density will be equal to 27 times the original one:
ρ₀ = m/ V₀
ρ₁ = m/ V₁ = m/ (V₀/27) = 27* (m/V₀) = 27*ρ₀
Answer:
the answer is B. Alpha particles, beta particles, and gamma rays
Explanation:
a p e x , i just took the quiz
Answer:
B. by blending in with the trees
Answer:
The gallon of milk is placed at a distance of 0.641 meters.
Explanation:
We have,
Mass of two 0.6 kg cartons of cereal is 1.2 kg
Length of the basket, l = 0.77 m
Center of the basket is 0.385 m
Mass of the half gallon of milk is 1.8 kg
Total weight in the basket is 1.2 + 1.8 = 3 kg
We need to find the position of the gallon of milk so that the center of mass (COM) of your groceries is at the center of the basket.
So,
(3 × 0.385) = (1.2 × 0) + (1.8 × x)
1.155 = 1.8 x
x = 0.641 meters
So, the gallon of milk is placed at a distance of 0.641 meters.
A) We want to find the work function of the potassium. Apply this equation:
E = 1243/λ - Φ
E = energy of photoelectron, λ = incoming light wavelength, Φ = potassium work function
Given values:
E = 2.93eV, λ = 240nm
Plug in and solve for Φ:
2.93 = 1243/240 - Φ
Φ = 2.25eV
B) We want to find the threshold wavelength, i.e. find the wavelength such that the energy E of the photoelectrons is 0eV. Plug in E = 0eV and Φ = 2.25eV and solve for the threshold wavelength λ:
E = 1243/λ - Φ
0 = 1243/λ - Φ
0 = 1243/λ - 2.25
λ = 552nm
C) We want to find the frequency associated with the threshold wavelength. Apply this equation:
c = fλ
c = speed of light in a vacuum, f = frequency, λ = wavelength
Given values:
c = 3×10⁸m/s, λ = 5.52×10⁻⁷m
Plug in and solve for f:
3×10⁸ = f(5.52×10⁻⁷)
f = 5.43×10¹⁴Hz