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3 years ago

How many ways can you write 5^8 as a quotient of two exponential terms? Explain your reasoning.

1 answer:

6 0

Exponents can be expressed in terms of quotient or fraction.
For example: x^6 can be expressed as x^8 / x^2 = x^8-2 = x^6.

From the question, 5^8 can be expressed as
5^10/5^2 = 5^8
(5^2)(5^8) / (5^2) = 5^8

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Hao has 16 gallons of water, he drinks one half gallon everyday, how many days will the water last?

Zarrin [17]

16 * 2 = 32
1 gal. = 2 half gal.

ans:32 days

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2 years ago

Which of the following is used to inscribe a square in a circle?

katrin [286]

Answer:

The option which is used to inscribe a square in a circle is option B

B. Construct a perpendicular bisector of the diameter of the circle

Step-by-step explanation:

The steps required to inscribe a square in a circle are;

1) Draw the circle using a compass

2) Draw the diameter of the circle, that passes through the center of the circle with a straight edge label the endpoint of the diameter X and Y

3) Construct the line perpendicular to the diameter of the circle and label the endpoints as A and B

The figure formed by joining the endpoints X, Y, A, and B is the inscribed square of the circle

Therefore, the correct option is to construct a perpendicular bisector of the diameter of the circle.

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3 years ago

Find the slope of the line passing through the points (-6, 6) and (4. – 7).

postnew [5]

Answer:

$\displaystyle -\frac{13}{10}$

Step-by-step explanation:

To solve this problem, first you have to use the slope formula of $\displaystyle \frac{y_2-y_1}{x_2-x_1}$ .

y2= (-7)

y1=6

x2=4

x1(-6)

Solve.

$\displaystyle \frac{(-7)-6}{4-(-6)}=\frac{-13}{10}=\boxed{-\frac{13}{10}}$

Therefore, the correct answer is -13/10.

6 0

3 years ago

Read 2 more answers

Please help with this question

Dafna1 [17]

The answer is (-2,-3) Thank you and please rate if I helped you! Thanks again!

4 0

2 years ago

Andrew claims the initial value and y - intercept are the same thing on a graph. Is he correct?

Agata [3.3K]

Answer:

We conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

Step-by-step explanation:

We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.

In other words, the initial value is the y-value or output of the point at x = 0

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the initial value of the equation y = 2x+1 is: y = 1

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Thus, at y = 1, the line meets the y-axis.

Hence, the initial value of the line is: y = 1

Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the y-intercept of y = 2x+1 is y = 1.

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Therefore, the y-intercept of y = 2x+1 is y = 1.

Conclusion:

Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

6 0

2 years ago