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Blizzard [7]
4 years ago
12

6th grade work help me please :)

Chemistry
1 answer:
MAVERICK [17]4 years ago
8 0

Answer:

the answer is option a. The sun stops shining

Explanation:

as water needs the sun's heat to evaporate into water vapour.

hope it helps :)

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Calculate the morality for the following<br> 10.5 kg of Na2 SO4. 10H2O in 18.60 L
Serggg [28]

Answer:

1.75M

Explanation:

The problem deals with finding the molarity of the given compound.

 The compound is:

             Na₂SO₄.10H₂O

Mass of the compound  = 10.5kg  = 10500g

Volume of the compound  = 18.6L

Molarity is the number of moles of solute in a solution;

     Molarity  = \frac{number of moles }{volume}  

 Number of moles  = \frac{mass}{molar mass}  

 Molar mass of   Na₂SO₄.10H₂O  = 2(23) + 32 + 4(16) + 10[2(1) + 16]

                                                       = 322g/mol

 Now;

    Number of moles  = \frac{10500}{322}   = 32.6mole

So;

  Molarity  = \frac{32.6}{18.6}   = 1.75M

5 0
3 years ago
Describe what parts are required to make an electric cell
qwelly [4]
U need positive and negative electordoe and an electrolyte <span />
3 0
4 years ago
How many protons neutrons and electrons are in 27 AI 3-
ira [324]

Hey there!

27 tells us the sum of protons and neutrons is 27.

Al tells us we have 13 protons.

3- tells us that there are 3 more electrons than protons.

13 + n = 27

neutrons = 14

13 + 3 = 16 electrons

27Al3- has 13 protons, 14 neutrons, and 16 electrons.

Hope this helps!

3 0
3 years ago
An atom of 110Sn has a mass of 109.907858 amu. Calculate the mass defect in amu/atom. Enter your answer with 4 significant figur
Oksi-84 [34.3K]
Do you still need help
3 0
3 years ago
Please help I’m timed !!!
Rashid [163]

Answer:

b. \% diss =4.4x10^{-2}\%

Explanation:

Hello there!

In this case, given the ionization reaction of HClO as weak acid:

HClO\rightleftharpoons H^++ClO^-

We can write the equilibrium expression as shown below:

Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}

In such a way, via the definition of x as the reaction extent, we can write:

3.5x10^{-8}=\frac{x^2}{[HClO]}

As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

x=\sqrt{3.5x10^{-8}*0.18} =\\\\x=7.94x10^{-5}M

And finally the percent dissociation:

\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%

Which is choice b.

Best regards!

6 0
3 years ago
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