1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p1
Primero realizas la configuración electrónica que es la que te puse allá arriba.
Después miras el nivel en que termina, puede ser 1, 2, 3, 4 etc.
Entonces como el último número de la configuración electrónica es 4, entonces ese es el nivel
Y los electrones de el último nivel son los de Valencia
4s2, 4p1 sumas 2+1 que son los electrones que se encuentran en el último nivel.
por eso hay 3 electrones de valencia.
Answer:
3.01×10²³ atoms of calcium
Explanation:
number of moles = number of atoms/Avogadro's constant
n = N/NA
N = n×NA = 0.500 mol×6.02×10²³ mol^-1
N = 3.01×10²³ atoms of calcium
A pure substance has "one set of universal properties". This means they have some of the universal properties in common.
<h3>The definition of universal property</h3>
A characteristic that describes some structures up to an isomorphism is known as a universal property in mathematics, more specifically in category theory.
As a result, independent of the construction technique used, some objects can be described using universal properties. For example, one can define polynomial rings as derived from the field of their coefficients, rational numbers as derived from integers, real numbers as derived from integers, and rational numbers as derived from real numbers.
All of these definitions can be made in terms of universal properties. In particular, the concept of universal property offers a simple demonstration of the equality of any real number structures, requiring only that they satisfy the same universal property.
<h3>
What is the universal property of all substances?</h3>
Diamagnetism is a feature that all substances share.
To learn more about Diamagnetism click on the link below:
brainly.com/question/22078990
#SPJ9
hydrogen and carbon, hope that helped
Answer:
The answers to your question are below
Explanation:
a) 6.85×1020 H2O2 molecules
H2O2 MW = 32 + 2 = 34 g
34g -------------------- 6.023 x 10²³ molecules
x ------------------- 6.85 x 10 ²⁰
x = (6.85 x 10 ²⁰)(34)/ 6.023 x 10²³
x = 0.038 g
3.3×1022 SO2 molecules
MW SO2 = 32 + 32 = 64g
64 g -------------------- 6.023 x 10²³ molecules
x -------------------- 3.3×1022 SO2 molecules
x = (3.3×1022 SO2)(64) / 6.023 x 10²³
x = 3.51 g
5.5×1025 O3 molecules
MW = 16 x 3 = 48g
48 g ----------------- 6.023 x 10²³ molecules
x ------------------ 5.5×1025 O3 molecules
x = (5.5×1025 )(48) / 6.023 x 10²³
x = 4383 g
9.30×1019 CH4 molecules
MW = 12 + 4 = 16 g
16 g -------------------- 6.023 x 10²³ molecules
x -------------------- 9.30×1019 CH4 molecules
x = (9.30×1019)(16) / 6.023 x 10²³
x = 0.0025 g
