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3 years ago

What is the ph of a 0.034 m hydrochloric acid solution?

Chemistry

2 answers:

Law Incorporation [45]3 years ago

8 0

PH= -log [H+]
= - (log 0.034)
= - (-1.5)
= 1.5

leva [86]3 years ago

4 0

Answer: The pH of the given HCl solution is 1.47

Explanation:

We are given:

Molarity of HCl = 0.034 M

1 mole of HCl produces 1 mole of hydrogen ions and 1 mole of chlorine ions.

pH is defined as negative logarithm of hydrogen ion concentration. It is basically defined as the power of hydrogen ions in a solution.

Mathematically,

$pH=-\log[H^+]$

We are given:

$[H^+]=0.034M$

Putting values in above equation, we get:

$pH=-\log(0.034)\\\\pH=1.47$

Hence, the pH of the given HCl solution is 1.47

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A colorless liquid has a molar mass of 60.01 g/mol. When the liquid was analyzed, it was 46.7% nitrogen and 53.3% oxygen. What i

MAXImum [283]

first we have to find the empirical formula of the compound

empirical formula is the simplest ratio of whole numbers of components making up a compound

for 100 g of the compound

N O

mass 46.7 g 53.3 g

number of 46.7 g/ 14 g/mol 53.3 g/ 16 g/mol

moles = 3.34 mol = 3.33 mol

divide by the least number of moles

3.34/3.33 = 1.00 3.33/ 3,33 = 1.00

therefore number of atoms are

N - 1

O - 1

empirical formula is - NO

mass of empirical unit - 14 g/mol + 16 g/mol = 30 g

molecular formula is actual composition of elements in the compound

molecular mass - 60.01 g/mol

number of empirical units = molecular mass / empirical unit mass

= 60.01 g/mol / 30 g = 2

there are 2 empirical units

2(NO)

molecular formula = N₂O₂

6 0

3 years ago

What is the voltage of a galvanic cell made with zinc (zn) and aluminum (al)?

bonufazy [111]

From the reduction standard potentials;
The emf of Zinc = -0.76 V
and the emf of Aluminium = -1.66 V
In a galvanic cell the component with lower standard reduction potential gets oxidized and that it is added to the anode compartment.
Therefore. the voltage of a galvanic cell made with zinc and aluminium will be;
Voltage =Ered- Eoxd
= -0.76 - (-1.66)
= 0.9 V

6 0

3 years ago

Read 2 more answers

What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy

daser333 [38]

Moles = n = 3.91 mol

Pressure = P = 5.35 atm

Temperature = T = 323 K

Volume = V = ?

Formula used: Ideal Gas Equation is used,

P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

V = 19.36 L

5 0

3 years ago

238,2U --> 234Th + 90

stiv31 [10]

Answer:

$\\_{2}^{4} \alpha$

Explanation:

In this question, we wish to find the missing nuclei for the equation:

$\\_{92}^{238} U\rightarrow _{90}^{234} Th + _{Z}^{A} X$

In order to find the missing species, we need to use the charge and mass balance law. That is, the mass should be conserved: the total mass on the left-hand side with respect to the arrow should be equal to the total mass on the right-hand side with respect to the arrow:

$238 = 234 + A$