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Varvara68 [4.7K]
3 years ago
8

Calculate the morality for the following 10.5 kg of Na2 SO4. 10H2O in 18.60 L

Chemistry
1 answer:
Serggg [28]3 years ago
5 0

Answer:

1.75M

Explanation:

The problem deals with finding the molarity of the given compound.

 The compound is:

             Na₂SO₄.10H₂O

Mass of the compound  = 10.5kg  = 10500g

Volume of the compound  = 18.6L

Molarity is the number of moles of solute in a solution;

     Molarity  = \frac{number of moles }{volume}  

 Number of moles  = \frac{mass}{molar mass}  

 Molar mass of   Na₂SO₄.10H₂O  = 2(23) + 32 + 4(16) + 10[2(1) + 16]

                                                       = 322g/mol

 Now;

    Number of moles  = \frac{10500}{322}   = 32.6mole

So;

  Molarity  = \frac{32.6}{18.6}   = 1.75M

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