Question

Calculate the morality for the following 10.5 kg of Na2 SO4. 10H2O in 18.60 L

Answer 1

Answer:

1.75M

Explanation:

The problem deals with finding the molarity of the given compound.

 The compound is:

             Na₂SO₄.10H₂O

Mass of the compound  = 10.5kg  = 10500g

Volume of the compound  = 18.6L

Molarity is the number of moles of solute in a solution;

     Molarity  = $\frac{number of moles }{volume}$  

 Number of moles  = $\frac{mass}{molar mass}$  

 Molar mass of   Na₂SO₄.10H₂O  = 2(23) + 32 + 4(16) + 10[2(1) + 16]

                                                       = 322g/mol

 Now;

    Number of moles  = $\frac{10500}{322}$   = 32.6mole

So;

  Molarity  = $\frac{32.6}{18.6}$   = 1.75M