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bixtya [17]
4 years ago
12

An electric bulb draws a current of 0.8A from 250 V mains. The bulb is used on an average 8

Physics
1 answer:
mihalych1998 [28]4 years ago
7 0
First, we must find the power consumed by the light bulb. This is given by:
Power = voltage * current
Power = 250 * 0.8
Power = 200 W = 0.2 kW

Now, we must calculate the number of hours that the bulb is used, as the price given to us is in Rs/kWh. This is:
8 hours per day * 30 days
= 240 hours

Total kWh = 0.2 * 240
Total kWh = 48 kWh

Bill = 3 * 48
Bill = 144 Rs
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WHY is it so important to include units when expressing numbers?
Natasha_Volkova [10]

Answer:

Without units, the results are unclear and it is hard to keep track of what each seperate measurement entails.

5 0
3 years ago
A runner completes the 200-meter dash with a time of 19.80 seconds. What was the runner's average speed in miles per hour?
andriy [413]

Answer:

v = 22.54 mph.

Explanation:

Given that,

Distance moved, d = 200 m

Time, t = 19.8 s

We need to find the runner's average speed.

We know that,

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200 m = 0.124 miles

19.8 seconds = 0.0055 h

So,

Speed = distance/time

v=\dfrac{0.124}{0.0055}\\\\v=22.54\ mph

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4 0
3 years ago
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3 0
3 years ago
What is the maximum mass of ethyl alcohol you could boil with 2000 j of heat, starting from 19 ∘c?
RSB [31]
The boiling point of ethanol is at 78.37°C. So, the energy must include sensible heat to raise 19°C to the boiling point and latent heat to change liquid to gas. The equation would be

Energy = Sensible heat + Latent heat
Energy = mCpΔT + mΔH

For ethanol, 
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Integrate the Cp expression to determine CpΔT:

CpΔT = ∫₂₉₂³⁵²(46.068 + 102,460T - 139.63T² - 0.030341T³ + 0.0020386T⁴ )dT
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CpΔT = 2384857192 J/kmol·K

2,000 J = m(2384857192 J/kmol)(1 kmol/1000 mol) + m(38,560 J/mol)
m = 8.253×10⁻⁴ moles of ethanol
Since the molar mass of ethanol is 46.07 g/mol,
Mass = (8.253×10⁻⁴ mol)(46.07 g/mol)
Mass = 0.038 g ethanol
8 0
4 years ago
What is the mechanical advantage of the following pulley? The pulley has six supporting
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Answer:

In a pulley, the ideal mechanical advantage is equal to the number of rope segments pulling up on the object. The more rope segments that are helping to do the lifting work, the less force that is needed for the job.

5 0
3 years ago
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