Question

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Answer 1

Answer:

The slope intercept  of the given line equation AB is $y = \frac{1}{2} ( x)- \frac{5}{2}$

Step-by-step explanation:

Here,the two given point s are A ( -9,-2) and B (1,3).

Now, the slope m of the line AB  =  $= \frac{y_2 - y_1}{x_2 -x_1}$

$\implies m = \frac{3 - (-2)}{1 - (-9)} = \frac{3+2}{1+9} = \frac{5}{10} = \frac{1}{2}$

or, the slope of line AB = 1/2

Now, the POINT SLOPE FORM of any equation with point (x0,y0) and slope m is given as :

y - y0 = m (x -x0)

So, the line equation of AB is given as :

$y - 3 = \frac{1}{2} ( x-1)\\\implies y =3 + \frac{1}{2} ( x-1)\\or, y = \frac{1}{2} ( x)- \frac{5}{2}$

SLOPE INTERCEPT form is y = mx + c

Hence, the slope intercept  of the given line equation AB is $y = \frac{1}{2} ( x)- \frac{5}{2}$