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4 years ago

12

If the Moon's orbit were perpendicular to the ecliptic, would eclipses be possible? What would be the most common phase of the M

oon? Why?

1 answer:

tangare [24]4 years ago

5 0

Answer:no

Explanation:

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Assume that a resistor is connected between the 150 V terminal and the common terminal. The voltmeter is then connected to an un

Lena [83]

Answer: $316.8V$

Explanation:

given data:

metre moving current = $0.96mA$

meters voltage = $288V$

or $0.96*300V = 288V$

<u><em>Solution:</em></u>

<u><em /></u> $v1 = (0.96mA*150)$ <u><em /></u>

<u><em /></u> $= 144V$ <u><em /></u>

<u><em /></u>

$i1 = \frac{144v}{750}$

$= 0.192mA$

$i2 = imovement + i1$

$i2= 0.96mA+0.192mA$

$= 1.152mA$

$Vmeasured = 144V+(150)(1.152mA)$

$=316.8V$

the unknown voltage is 316.8V

7 0

3 years ago

Will mark as BRAINLIEST....... The Displacement x of particle moving in one dimension under the action of constant force is rela

pentagon [3]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

$x=4t^3+3t^2-5t+2$

Where,

x is in meters and t is in sec

We know that,

Velocity,

$v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5$

(a) i. t = 2 s

$v=12(2)^2+6(2)-5=55\ m/s$

At t = 4 s

$v=12(4)^2+6(4)-5=211\ m/s$

(b) Acceleration,

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6$

Pu t = 3 s in the above equation

So,

$a=24(3)+6\\\\a=78\ m/s^2$

Hence, this is the required solution.

3 0

3 years ago

John runs around a 126.5 m circular track 3.5 times in 4.17 minutes. What is his average speed?

sdas [7]

Average speed = distance traveled / time

average speed = (126.5 m * 3.5 laps) / (4.17 min)

= 106.2 m/min

6 0

3 years ago

Define limitations in the operation conditions of a pn junction<br>

suter [353]

Answer:

Such limitations are given below.

Explanation:

Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.
If controlled within certain adsorption conditions, the pn junction could very well offer satisfying performance.
In connector operation, the maximum inversion voltage seems to be of significant importance.

6 0

4 years ago

Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th

Ymorist [56]

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

$v_2=\frac{34\ g.m/s}{6\ g}\\\\$

<u>v₂ = 5.7 m/s</u>

<u></u>

Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

4 0

3 years ago