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Gemiola [76]
3 years ago
15

Find a polynomial f(x) of degree 4 that has the following zeros.

Mathematics
1 answer:
34kurt3 years ago
3 0

Answer:

The answer to your question is     (x₁ - 4)(x₂ - 9)(x₃)(x₄ +4)

Step-by-step explanation:

Data

zeros of a polynomial  = 4, 9, 0, -1

Process

1.- Equal each root to zero

   x₁ = 4     x₂ = 9    x₃ = 0    x₄ = -1

  x₁ - 4 = 0    x₂ - 9 = 0     x₃ = 0    x₄ + 1 = 0

2.- Write the terms together

   (x₁ - 4)(x₂ - 9)(x₃)(x₄ +4)

3.- Expand to check the answer

   (x - 4)(x - 9) = x² -13x + 36

   (x² -13x + 36)(x) = x³ - 13x² + 36x

   (x³ - 13x² + 36x)(x + 4) = x⁴ - 13x³ + 36x² + 4x³ - 52x² + 144x

                                        = x⁴ - 9x³ - 16x² + 144

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In the drawing below, find x if ABCD is a square and angle B= 4x + 10.
iragen [17]

Answer:

x=20

Step-by-step explanation:

4x +10 = 90

-10 from both sides

that gives you 4x=80

80 divided by 4 gives you 20=x

6 0
3 years ago
Please answer right away
Ilya [14]

Answer:

6.13

Step-by-step explanation:

Using Sine Law we know that

\dfrac{a}{SinA}=\dfrac{b}{SinB}=\dfrac{c}{SinC}

Using your figure let's assign sides and angles:

A=? B = 60° C = 70°

a = 5 b = ? c = x

If we put that into our formula:

\dfrac{5}{Sin?}=\dfrac{?}{Sin60}=\dfrac{x}{Sin70}

Notice that we have too many unknowns. We need to complete at least one ratio to do this, so how do we do this?

Notice we have 2 angles given, so we solve for the third angle. The sum of all angles in any triangle is always 180°

∠A + ∠B + ∠C= 180°

∠A + 60° + 70° = 180°

∠A + 130° = 180°

∠A = 180° - 130°

∠A = 50°

Now we can use this to solve for x.

\dfrac{5}{Sin50}=\dfrac{x}{Sin70}\\\\\dfrac{(5)(Sin70)}{Sin50} = x\\\\\dfrac{4.6985}{0.7660}=x\\\\6.1338 =x

So the closest answer would be 6.13

5 0
3 years ago
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What is the average rate of change <br>y - 3 = -12 (x + 4)​​
vagabundo [1.1K]

Answer:

- 12x

Step-by-step explanation:

y - 3 =  - 12(x + 4) \\ y - 3 =  - 12x - 48 \\ y =  - 12x - 45

Thr answer is the slope.

4 0
3 years ago
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3 years ago
A student claims that 8^3 x 8^-5 is greater than 1. Explain whether the student is correct or not.
nlexa [21]
Remember:
a^m * a^n=a^(m+n)
a^-m=1/a^m


8³ x 8⁻⁵=8³⁻⁵=8⁻²=1/8²=1/64<1

Answer: the student is not correct, because 1/64<1, and 8³ x 8⁻⁵=1/64.
7 0
3 years ago
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