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spayn [35]
3 years ago
11

Solve for kx+ 3x= 4 for x

Mathematics
1 answer:
irina1246 [14]3 years ago
5 0

Answer

k

Step-by-step explanation:

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Which model best fits the data shown in the scatterplot?
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Answer:

<u>A. y = -0.7x + 1.9</u>

Step-by-step explanation:

  • The y-intercept is roughly +2 as you can see from the scatterplot therefore ⇒ Not option C or D [both of which are negative]
  • The slope is slanted from top left to right bottom [meaning the slope is negative] ⇒ Not B
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Assume that X is a binomial random variable with n = 27 and p = 0.90. Calculate the following probabilities. (Do not round inter
Yuki888 [10]

Answer:

a) P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744

b) P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

c) P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744

P(X=27) = 27C27 (0.9)^{27} (1-0.9)^{27-27}= 0.0582

And addind the values we got:

P(X\geq 25)= P(X=25)+P(X=26)+P(X=27)=0.2520+0.1744+0.0582=0.4846

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=27, p=0.9)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Part a

We want this probability:

P(X=26)

And we can use the probability mass function and we got:

P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744

Part b

We want this probability:

P(X=25)

And we can use the probability mass function and we got:

P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

Part c

We want this probability:

P(X\geq 25)= P(X=25)+P(X=26)+P(X=27)

And we can use the probability mass function and we got:

P(X=25) = 27C25 (0.9)^{25} (1-0.9)^{27-25}= 0.2520

P(X=26) = 27C26 (0.9)^{26} (1-0.9)^{27-26}= 0.1744

P(X=27) = 27C27 (0.9)^{27} (1-0.9)^{27-27}= 0.0582

And addind the values we got:

P(X\geq 25)= P(X=25)+P(X=26)+P(X=27)=0.2520+0.1744+0.0582=0.4846

3 0
3 years ago
- 7s+12=-9s what is the answer
weqwewe [10]
12=-9s+7s
12=-2s
-6=s
Hope this helps
6 0
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