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4 years ago

How do work 3x-2y=3 and 5x-5y=10

1 answer:

4 0

Those equations are in standard form. to graph them you need to put it in y=mx+b form, also known as slope intercept form. if they are a system of equations and u have to fins where they intersect then put it in slope intercept form and see the point where they meet. if they are separate and u only need to graph each of them again, they need to be in slope intercept form. 3x-2y=3 is y=3/2x+3 and 5x-5y=10 is y=x+3 if you put it in slope intercept form.

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M= -3 b= -1 slope intercept form

Aliun [14]

Answer:

y = -3x-1

Step-by-step explanation:

all u had to do was plug it into y = mx+b

5 0

3 years ago

< Exit

Roman55 [17]

Answer:

88m of fencing

Step-by-step explanation:

the cicumference of the garden is what we are looking out for,

and with the raduis .ie.14m

C=2πr

C=2•22/7•14

C=88m

8 0

3 years ago

A $16,000 robot depreciates linearly to zero in 10 years. (a) find a formula for its value as a function of time, t, in years.

SVETLANKA909090 [29]

We are given, cost of the robot for 0 number of year = $16,000.

0 represents initial time of the robot.

After 10 year cost of the robot is = $0

The problem is about the number of the years and cost of the robot over different number of years.

So, we could take x coordinate by number of hours and y coordinate for y number of hours.

So, from the problem, we could make two coordinates for the given situation.

(x1,y1) = (0, 16000) and (x2,y2) = (10, 0).

In order to find the function of time, we need to find the rate at which robot rate depreciates each year.

Slope is the rate of change.

So, we need to find the slope of the two coordinates we wrote above.

We know, slope formula

$Slope (m) = \frac{y2-y1}{x2-x1}$

Plugging values in formula, we get

$m=\frac{0-16000}{10-0} = \frac{-16000}{-10} = -1600.$

Brecasue of depreciation we got a negative number for slope or rate of change.

Therefore, rate of depreciation is $1600 per year.

We already given inital cost, that is $16,000.

So, we can setup an a function

f(x) = -1600x + 16000.

But the problem is asked to take the variable t for time.

Replacing x by t, we get

f(t) = -1600t + 16000.

8 0

3 years ago

What is the height of the tv and is it square inches or inches ??

fiasKO [112]

To find the height of the TV you first need to realize that the question is giving you dimensions for a triangle.

Every triangle has a hypotenuse and two sides. To find the hypotenuse you square both sides, add them, and then square root. So to find one of the sides you get the hypotenuse, square it, and subtract the square length of the given side.

The equation is 25^2-20^2.
Which if simplified is 625-400, the then solution is going to be 225.
You next will square root 225, 225^(1/2). Which your answer should be 15 inches for the missing side length.

7 0

4 years ago

Read 2 more answers

A certain virus infects one in every 400 people. A test used to detect the virus in a person is positive 90% of the time if the

Ahat [919]

Answer:Given:

P(A)=1/400

P(B|A)=9/10

P(B|~A)=1/10

By the law of complements,

P(~A)=1-P(A)=399/400

By the law of total probability,

P(B)=P(B|A)*P(A)+P(B|A)*P(~A)

=(9/10)*(1/400)+(1/10)*(399/400)

=51/500

Note: get used to working in fraction when doing probability.

(a) Find P(A|B):

By Baye's Theorem,

P(A|B)

=P(B|A)*P(A)/P(B)

=(9/10)*(1/400)/(51/500)

=3/136

(b) Find P(~A|~B)

We know that

P(~A)=1-P(A)=399/400

P(~B)=1-P(B)=133/136

P(A∩B)

=P(B|A)*P(A) [def. of cond. prob.]

=9/10*(1/400)

=9/4000

P(A∪B)

=P(A)+P(B)-P(A∩B)

=1/400+51/500-9/4000

=409/4000

P(~A|~B)

=P(~A∩~B)/P(~B)

=P(~A∪B)/P(~B)

=(1-P(A∪B)/(1-P(B)) [ law of complements ]

=(3591/4000) ÷ (449/500)

=3591/3592

The results can be easily verified using a contingency table for a random sample of 4000 persons (assuming outcomes correspond exactly to probability):

===....B...~B...TOT

..A . 9 . . 1 . . 10

.~A .399 .3591 . 3990

Tot .408 .3592 . 4000

So P(A|B)=9/408=3/136

P(~A|~B)=3591/3592

As before.

Step-by-step explanation: its were the answer is

5 0

3 years ago