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liraira [26]
3 years ago
7

What is the line of reflection for the trapezoids? On a coordinate plane, trapezoid A B C D has points (5, 4), (6, 4), (8, 3) an

d (5, 3). Trapezoid A prime B prime C prime D prime has points (1, 4), (0, 4), (negative 2, 3), (1, 3). x = 3 y = 3 x-axis y-axis
Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

x=3

Step-by-step explanation:

Anna11 [10]3 years ago
6 0

Answer:

The answer to this question is x=3

Step-by-step explanation:

If you create the graph and then plot the points you will get a depiction of the trapazoids. using this you will find that they have reflected over the x=3 line.

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4ax+by=3 , 6ax+5by=8
Andrews [41]
1. x=3-by/4a
2. x=8-5by/6a
8 0
3 years ago
Jessica used 2/3 yard of fabric to make a scarf. Can she make 2 of these scarves with
mr Goodwill [35]
Yes because 
1 3/4 is 7/2 and 2/3+2/3=4/3

So yes he can 
Hope this helps :-P

5 0
3 years ago
Read 2 more answers
Find the first four terms of the sequence given by the following.<br> aₙ=43-3(n-1) n=1,2,3. . .
Serggg [28]

Given :-

  • The general term of a sequence is given by aₙ=43-3(n-1) .

To Find :-

  • The first four terms of the sequence.

Solution :-

The given expression is /

→ aₙ=43-3(n-1)

where n > 0

<u>Finding</u><u> the</u><u> </u><u>first </u><u>term </u><u>:</u>

Substituting n = 1 , we have ,

→ T1 = 43 - 3(1-1)

→ T1 = 43 - 3*0

→ T1 = 43 - 0 = 43

<u>Finding</u><u> the</u><u> </u><u>second</u><u> </u><u>term </u><u>:</u>

Substituting n = 2 , we have,

→ T2 = 43 -3(2-1)

→ T2 = 43 -3*1

→ T2 = 43 -3 = 40

<u>Finding</u><u> </u><u>the </u><u>third </u><u>term</u><u> </u><u>:</u>

Substituting n = 3 , we have,

→ T3 = 43 -3(3-1)

→ T3 = 43 -3*2

→ T3 = 43 -6 = 37

<u>Finding</u><u> the</u><u> </u><u>fourth</u><u> </u><u>term </u><u>:</u>

→ T4 = 43 -3(4-1)

→ T4 = 43 -3*3

→ T4 = 43-9 = 34

<u>Hence</u><u> the</u><u> </u><u>first</u><u> </u><u>four</u><u> terms</u><u> of</u><u> </u><u>the</u><u> </u><u>sequence</u><u> </u><u>are </u><u>4</u><u>3</u><u> </u><u>,</u><u> </u><u>4</u><u>0</u><u> </u><u>,</u><u> </u><u>37</u><u> </u><u>and </u><u>34</u><u> </u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em><em> </em><em>Let </em><em>me</em><em> know</em><em> if</em><em> you</em><em> </em><em>need </em><em>further</em><em> </em><em>clarification</em><em> </em><em>.</em>

7 0
2 years ago
Pls help me out with this question
olga2289 [7]

Answer:

HL

Step-by-step explanation:

The things that are congruent between the 2 triangles are the 90° angles and the hypotenuses and legs. HA and LA only work with the acute angles, not right angles, and AA isn't a way of proving things to be congruent, meaning that HL is the answer

3 0
3 years ago
Read 2 more answers
Emily purchased lemons for $600. She sold 3/4 of these at a loss of 20% and the remaining at a gain of 20%. How much percent doe
MAVERICK [17]

Answer:

10%

Step-by-step explanation:

Given: CP of lemon is $600.

           3/4 of lemon sold at 20% loss

           Remaining lemon at 20% gain.

Considering the quantity of lemon remain constant.

Cost price of 3/4 of lemon= \frac{3}{4} \times 600= \$450

As given, 3/4 of lemon sold at 20% loss.

∴ Selling price of \frac{3}{4}\ of\ lemon=  450- \frac{20}{100}\times 450

Selling price= 450- 90= \$ 360

Hence, selling price of 3/4 lemon is $360.

Now, the cost price of remaining lemon (1-\frac{3}{4} )= (\$ 600-\$ 450)

∴ The cost price of \frac{1}{4}\ lemon = \$ 150

As given, remaining \frac{1}{4} lemon\ sold\ at\ gain\ of\ 20\%

∴ Selling price of \frac{1}{4} \ lemon= (150\times \frac{20}{100}+150)

Selling price of \frac{1}{4} \ of\ lemon= (30+150)

Hence, selling price of 1/4 lemon is $180

Loss\profit percent= \frac{(SP-CP)}{CP} \times 100

∴ Loss\profit percent= \frac{60}{600} \times 100= 10\%

Hence, the loss percentage is 10%

8 0
3 years ago
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