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Law Incorporation [45]
3 years ago
14

What are thermal plasmas

Chemistry
1 answer:
Colt1911 [192]3 years ago
3 0
Have electrons and the heavy particles at the same temperature, i.e. they are in thermal<span> equilibrium with each other.</span>
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What sphere interacts when chemicals in the Air cause Weathering to Rocks? *
miss Akunina [59]
The answer is A. atomosphere yamp ; biosphere
4 0
3 years ago
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URGENT!!!!!!! 15 POINTS!!!!!
Doss [256]

The true statement should be B

the electron configuration for Phosphorous is 1s2 2s2 2p6 3s2 3p3

the diagram for 3p3 should be ^_ ^_ ^_ because you want to fill to put an electron in each slot before you double up

6 0
3 years ago
Find the initial temperature of 45.0g of water if its final Temperature after submerging a metal with the mass of 8.5g is 22.0°C
Korolek [52]

The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

<em>"Your question is not complete, it seems to be missing the following information;"</em>

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

  • <em>mass of water, </em>m_w<em> = 45 g</em>
  • <em>final temperature of the water, </em>t_w<em> = 22 ⁰C</em>
  • <em>mass of the metal, m = 8.5 g</em>
  • <em>initial temperature of the metal, t = 82 ⁰C.</em>
  • <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

<em>heat gained by water = heat lost by metal</em>

Q_{water} = Q_{metal}

m_wc_w \Delta t_w = mc\Delta t

where;

c_w <em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>

<em />

<em>Substitute the given values;</em>

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16  - 188.28t = 240.98

188.28t  = 4142.16  - 240.98

188.28t  = 3901.18

t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

Learn more here:brainly.com/question/15345295

8 0
3 years ago
4. To how much water should 50 mL of 12 M hydrochloric acid be added to
Novosadov [1.4K]

Answer : The volume of water added are, 15 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of HCl.

M_2\text{ and }V_2 are the final molarity and volume of water.

We are given:

M_1=12M\\V_1=50mL\\M_2=40M\\V_2=?

Putting values in above equation, we get:

12M\times 50mL=40M\times V_2\\\\V_2=15mL

Hence, the volume of water added are, 15 mL

7 0
3 years ago
How much does nestle pay the local municipality for access to their spring water
BlackZzzverrR [31]

Around 750 to 1,500.

     Hope I helped!

4 0
3 years ago
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