Question

4. To how much water should 50 mL of 12 M hydrochloric acid be added to

Answer 1

Answer : The volume of water added are, 15 mL

Explanation :

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of HCl.

$M_2\text{ and }V_2$ are the final molarity and volume of water.

We are given:

$M_1=12M\\V_1=50mL\\M_2=40M\\V_2=?$

Putting values in above equation, we get:

$12M\times 50mL=40M\times V_2\\\\V_2=15mL$

Hence, the volume of water added are, 15 mL