Two fish swimming in a river have the following equations of motion:
1 answer:
Answer:
The second fish, X2, is moving faster than the first fish, X1
Explanation:
The given parameters for the equation of motion of the fishes are;
X1 = -6.4 m + (-1.2 m/s)×t
X2 = 1.3 m + (-2.7 m/s)×t
The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes
For the first fish, the intercept = -6.4 m, the slope = the speed = -1.2 m/s
For the second fish, the intercept = 1.3 m, the slope = the speed = -2.7 m/s
Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;
The magnitude of the speed of the second fish , is larger than the magnitude of the speed of the first fish
Therefore, the second fish, X2, is moving faster than the first fish, X1.
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Answer:
The electric field at origin is 3600 N/C
Solution:
As per the question:
Charge density of rod 1,
Charge density of rod 2,
Now,
To calculate the electric field at origin:
We know that the electric field due to a long rod is given by:
Also,
(1)
where
K = electrostatic constant =
R = Distance
= linear charge density
Now,
In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.
At x = - 1 cm = - 0.01 m:
Using eqn (1):
(towards)
Now, at x = 1 cm = 0.01 m :
Using eqn (1):
(towards)
Now, the total field at the origin is the sum of both the fields: