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4 years ago

Which errors might occur when measuring length of object

Physics

1 answer:

Alexus [3.1K]4 years ago

6 0

Answer:

Generally errors are classified into three types: systematic errors, random errors and blunders. Gross errors are caused by mistake in using instruments or meters, calculating measurement and recording data results.Measurement Error (also called Observational Error) is the difference between a measured quantity and its true value. It includes random error (naturally occurring errors that are to be expected with any experiment) and systematic error (caused by a mis-calibrated instrument that affects all measurements).

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Find the length of a microscope having magnifying power 100, if the focal lengths of the objective and eye piece are 2 cm and 5

sp2606 [1]

Answer:

L = 40 cm

Explanation:

A microscope is an optical instrument built by two lenses in such a way that the image of the first is formed within the distance of the other (eyepiece), so that the latter creates an enlarged virtual image of the object, for which the magnification of the microscope is the same to the multiplication of the magnification of each lens

M = - L / f₀ (25 cm / $f_{e}$ )

where fo and fe are the focal lengths of the objective and eyepiece, 25 cm is the near vision distance and L is the length of the microscope

L = - M f_{o} f_{e} / 25

let's calculate

L = - (-100) 2 5/25

L = 40 cm

7 0

3 years ago

How would i solve these problems, nobody in my class understands and there is a substitute

DiKsa [7]

1) X-component: 568.5 N, Y-component: 511.9 N

2) The horizontal force is 86.6 N and the resulting acceleration is $0.87 m/s^2$

Explanation:

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

$F_x = F cos \theta\\F_y = F sin \theta$

where

F = 765 N is the magnitude of the force

$\theta=42.0^{\circ}$ is the angle of the force with the horizontal

Substituting, we find:

Horizontal component: $F_x = (765)(cos 42.0^{\circ})=568.5 N$
Vertical component: $F_y = (765)(sin 42.0^{\circ})=511.9 N$

First of all, we have to find the horizontal component of the pulling force, which is given by

$F_x = F cos \theta$

where

F = 100 N is the magnitude of the pulling force

$\theta=30.0^{\circ}$ is the direction of the force with the horizontal

Substituting,

$F_x = (100)(cos 30^{\circ})=86.6 N$

Now we can find the acceleration of the wagon by using Newton's second law:

$F_x = ma_x$

where

$F_x = 86.6 N$ is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

$a_x$ is the acceleration in the horizontal direction

Solving for $a_x$ , we find

$a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2$

Learn more about vector components:

brainly.com/question/2678571

And about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0

3 years ago

The lens of the eye focuses light on the

pav-90 [236]

Answer

Cornea

Explanation:

The lens is composed of transparent, flexible tissue and is located directly behind the iris and the pupil. It is the second part of your eye, after the cornea, that helps to focus light and images on your retina.

4 0

4 years ago

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I NEED THIS ASAP<br> What does the satellite image below represent?

motikmotik

It might be a low pressure

6 0

3 years ago

A box is sliding along a frictionless surface and gets to a ramp. Disregarding friction, how fast should the box be going on the

levacccp [35]

This is amazing. When you read the quest ion, you wouldn't think there's enough information there to find an answer. But there is !

-- When the block is sliding along the flat surface, its kinetic energy is (1/2)(Mass·v²).

-- When it's 2.5m up the ramp and stops, its potential energy is (2.5m)·(Mass·g).

-- If there's no friction anywhere, these energies are equal.

(1/2)(Mass·v²) = (2.5m)·(Mass·g)

(v²/2) = (2.5m) · g

v² = 5m · g

v² = 49 m²/s²

<em>v = 7 m/s </em>(B)

9 0

3 years ago

Read 2 more answers

Which errors might occur when measuring length of object​

Which errors might occur when measuring length of object