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Fofino [41]
4 years ago
12

What scientist uses a metric ruler

Chemistry
1 answer:
attashe74 [19]4 years ago
4 0
Geologists use a metric ruler
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In your double replacement reaction, the more reactive metal "pushed" the other one out of its place. Without using the Internet
irakobra [83]
You are using the internet right now. The question told you not to. Lol
5 0
3 years ago
O
viva [34]

Answer:

The second and third option are isotopes of Bromine

Z=  35 A = 79

A = 79  N= 44

Explanation:

Step 1: What are isotopes ?

⇒ Elements  with same atomic number (Z) ( this means the same number of electrons and protons) but a different number of neutrons (N)

The atomic number (visible on the periodic table) is the number of protons.

The atomic mass is  the sum of the protons (Z) and neutrons (N), and is showed as 'A'. So A = Z+N

If we look at the periodic table, we can see that the atomic number of bromine (Z) = 35. This means the amount of protons = 35. Since isotopes have the same amount of protons, all isotopes of bromine, have 35 protons.

1) Z = 79, A = 196

Z = protons = electrons .So this element has 79 protons, as well as 79 electrons.

196 = 79 + N ⇒ N = 196 - 79 = 117 neutrons

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Gold (Au): 196Au

2) Z = 35 , A = 79

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons.

79 =35 + N ⇒ N = 79 - 35= 44 neutrons

⇒Since it does have 35 protons, it is an isotope of Bromine. This isotope has 44 neutrons

⇒ This is 79Br, which is a stable isotope of Bromine.

3) A=79, N = 44

Z = A - N ⇒ Z = 79 - 44 = 35

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons. It also has 44 neutrons.

⇒Since it does have 35 protons, it is an isotope of Bromine, with 44 neutrons: 79Br

4) Z = 44, N = 44

Z = protons = electrons .So this element has 44 protons, as well as 44 electrons.

A = 44 + 44 ⇒ A = 88  

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Ruthenium (Ru) : 88Ru

⇔So the <u>second</u> and<u> third</u> option are isotopes of Bromine

6 0
3 years ago
Every ribosome has three tRNA binding sites: the A site, the P site, and the E site. For the given sentences, select the correct
alex41 [277]

Answer:

A. All sites B. A site C. E site D. P site

Explanation:

A. Because all sites consequently take place while peptide is synthesized.

B. A site (aminoacyl site) is called so because it binds to charged aminoacyl peptide.

C. Because it is the exit site and it takes the final stage on the uncharged molecule.

D. The P site (peptidil site which takes main role in peptide synthesis.

8 0
3 years ago
Read 2 more answers
carbon disulfide is formed by the reaction of coke (carbon) with sulfur dioxide. how many moles of cs2 will be generated if 8.0
DerKrebs [107]
The balanced chemical reaction:

<span>5C + 2SO2 → CS2 + 4CO
</span>
We are given the amount of coke to be used for the reaction. This will be the starting point for the calculations.

8 mol C ( 1 mol CS2 / 5 mol C ) = 1.6 mol CS2
5 0
3 years ago
Describe the steps to balancing a chemical equation.
scZoUnD [109]
Identify each element found in the equation. The number of atoms of each type of atom must be the same on each side of the equation once it has been balanced.

What is the net charge on each side of the equation? The net charge must be the same on each side of the equation once it has been balanced.

If possible, start with an element found in one compound on each side of the equation. Change the coefficients (the numbers in front of the compound or molecule) so that the number of atoms of the element is the same on each side of the equation. Remember, to balance an equation, you change the coefficients, not the subscripts in the formulas.

Once you have balanced one element, do the same thing with another element. Proceed until all elements have been balanced. It's easiest to leave elements found in pure form for last.

Check your work to make certain the charge on both sides of the equation is also balanced.
6 0
4 years ago
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