Answer:
The Ka is 3.74 *10^-4
Explanation:
Step 1: Data given
Mass of aspirin = 2.00 grams
Volume of water = 0.600 L
pH of solution = 2.61
Molar mass of acetylsalicylic acid = 180 g/mol
Step 2: The balanced equation
C9H8O4 + H2O ⇆ H3O+ + C9H7O4-
Step 3: Calculate moles acetylsalicylic acid
Moles acetylsalicylic acid = mass / molar mass
Moles acetylsalicylic acid = 2.00 grams / 180 g/mol
Moles acetylsalicylic acid = 0.0111 moles
Step 4: The initial concentration
[C9H8O4] = 0.0111 moles / 0.600 L = 0.0185 M
[H3O+] = 0M
[C9H8O4-] = 0M
Step 5: The concentration at the equilibrium
[C9H8O4] =0.0185 - X M
[H3O+] = XM
[C9H8O4-] = XM
Step 6: Calculate Ka
Ka = [H3O+][C9H7O4-] / [C9H8O4]
Ka = x² / (0.0185 - x)
pH = 2.61; [H3O+] = 10^-pH = 10^-2.61 = 0.00245 = x
Ka = (0.00245)² / (0.0185 - 0.00245) = 3.74 * 10^-4
The Ka is 3.74 *10^-4
65 Grams is the mass of the beaker because you just take the mass of Water + Beaker and take the water away now you have the mass of the beaker
Answer: D is right
Explanation: One mole contains 6.0225 ·10^23 molecules
Despite of the substance
Answer:
3.84 Ω
Explanation:
From the question given above, the following data were obtained:
Electrical power (P) = 150 W
Voltage (V) = 24 V
Resistance (R) =?
P = IV
Recall:
V = IR
Divide both side by R
I = V/R
P = V/R × V
P = V² / R
Where:
P => Electrical power
V => Voltage
I => Current
R => Resistance
With the above formula (i.e P = V²/R), we can calculate resistance as illustrated below:
Electrical power (P) = 150 W
Voltage (V) = 24 V
Resistance (R) =?
P = V²/R
150 = 24² / R
150 = 576 / R
Cross multiply
150 × R = 576
Divide both side by 150
R = 576 / 150
R = 3.84 Ω
Thus, the resistance is 3.84 Ω
THE ANSWER IS I.ASTEROIDS II.COMETS III. METEOROIDS IV. PLANETS PLZ MARK BRAINLISEST HOPE I HELPED THX
