3 years ago

Calculate the pH of a 0.30 M NaF solution. The Ka value for HF is 7.2*10^-4

1 answer:

5 0

We are given with the equilibrium constant of acid, HF and is asked to calculate the pH of 0.30 M NaF solution. The formula to be followed is
Ka = [H+][F-]/[HF]Ka = 7.2 x 10 -4 = x^2/[0.3-x]x = [H+]= pH = -log (H+) = 1.84

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