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Harrizon [31]
3 years ago
7

Plz please help urgent ​

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0

Answer :

\frac{8}{125}  = ( \frac{2}{5} )^{3} = 0.064

Stolb23 [73]3 years ago
3 0

Answer:

0.064

Step-by-step explanation:

solve the btackets first then the powers then start multiplying

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HELP PLSSS, 20 POINTSSS
ruslelena [56]

Answer:

m1=43

Step-by-step explanation:

78-35=43

8 0
3 years ago
Read 2 more answers
HELP PLEASE ITS THE ONLY QUESTION I NEED!!
insens350 [35]

Because the order doesn't matter on where each person sits use the combinations formula:

C = n! / (r!(n-r)!)

Where n is the total number of people and r is the number of chairs.


C = 6! / (4!(6-4)!)

C = (6*5*4*3*2*1) / ((4*3*2*1(2*1))

C = 720 / (24*2)

C = 720 / 48

C = 15


There are 15 different arrangements.

6 0
2 years ago
Read 2 more answers
Given f (x) = -3x - 1, solve for x when f (x) = -4
Aleks [24]
Answer:
11
Explanation:
f(x) = -3x - 1 when f(x) = -4
f(x) = -4 * -3 -1 = 12 - 1 = 11
8 0
3 years ago
The quadratic function g(x) = a.ca + bx+c has the
Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

f(x)=ax^2+bx+c

Here we know that the leading coefficient a=1 so we reduce our equation to:

g(x)=x^2+bx+c

The roots are those values at which g(x)=0

So:

x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\  49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\

Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\  49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0

So we have:

(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}

Finding c from (1):

33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0
3 years ago
Need help ASAP plz I have to finish but I’m stuck here
labwork [276]
Ello I think it could be B
8 0
3 years ago
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