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Alex
4 years ago
11

How to find the lcm of 4 and. 2 2/3

Mathematics
1 answer:
Mkey [24]4 years ago
5 0
The lowest common multiple or least common multiple is the lowest multiple two numbers have in common.
you could either:
•list the multiples
eg. What is the lowest common multiple of 2 and 3?
Multiples of 2: 2, 4, 6, 8...
Multiples of 3: 3, 6, 9...
The lowest common multiple of 2 and 3 is 6.

• or factors.
eg. The prime factors of 25 are 5 x 5.
The prime factors of 30 are 2 x 3 x 5.
Remove the 5 that 25 and 30 have in common as a prime factor.
Multiply 25 by the remaining prime factors of 30.
25 x 2 x 3 = 150.
The lowest common multiple of 25 and 30 is 150.

that’s not how to find the lowest of those numbers, but that’s how to do it :))
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In a right triangle, the base is 12 m and the hypotenuse is 15 m. What is the length of height?
vovikov84 [41]

Answer:

L = Hyp²-B²

L=15²-12²

L =225 - 144 = 81

L= √81=9

<h3>L= 9m</h3>
4 0
3 years ago
4 × (h ×5) = (4 × h) ×5
Sholpan [36]

Answer:c.

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Step-by-step explanation:

5 0
3 years ago
Given: ΔABC, AC = BC, AB = 3 CD ⊥ AB, CD = √3 Find: AC
valina [46]

Answer:

\boxed{AC = 2.3}

Step-by-step explanation:

AD = BD  (CD bisects AB means that it divides the line into two equal parts)

So,

AD = BD = AB/2

So,

AD = 3/2

AD = 1.5

<u><em>Now, Finding AC using Pythagorean Theorem:</em></u>

c^2 = a^2+b^2

Where c is hypotenuse (AC), a is base (AD) and b is perpendicular (CD)

AC^2= (1.5)^2+(\sqrt{3} )^2

AC^2 = 2.25 + 3

AC^2 = 5.25

Taking sqrt on both sides

AC = 2.3

3 0
3 years ago
Read 2 more answers
How long is 3/4 of an hour
user100 [1]
3/4 of an hour is <span>45 minutes.</span>
5 0
4 years ago
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if 40 percent of a circle is taken what would be the angle you would draw to represent 40 percent of the circle
Tema [17]
If you mean 40% of the circle with the rotation at the center of the circle, then you do this:
Measure of circle: 360°
Amount of circle's measure: 40%
360 * 40% = 144°

Thus, to take up 40% of the circle you need to have an angle measure of 144°.
6 0
3 years ago
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