(2×12×200.50)÷(2,500×25) *100=7.7%
Answer:
5.5 liters
Step-by-step explanation:
1 milliliter equals to 1/1000 part of a liter, which is 0.001 liter.
1 milliliter = 1 * 0.001 liter
So if you have 5500 milliliters that means it equals to 5500 times one milliliters and 1 milliliter = 1 * 0.001 liter, so for 5500 milliliters it is 5500 times as much
5500 * 0.001
5500 * 1/1000
5500 / 1000
5.5 liters
As long as you know this number 0.001 , then it is easily to calculate between liters and milliliters.
EXTRA:
To convert from amount A which is given in a certain quantity, to another quantity, you sometimes have to multiply and in other cases you need to divide by a certain factor. The factor defines the relationship between the quantities.
Suppose you have 1000 times 1 milliliter then you can find the amount in liters by multiplying that number of milliliters times 0.001.
It is easy to see that
1000 * 1/1000
1000 / 1000
= 1 liter, but that is easy, because I choose an easy number for the amount of milliliters to convert into liters. But it works exactly the same for any amount!
a 230 metersa 230 metersa 230 metersa 230 metersa 230 metersa 230 metersa 230 metersa 230 metersa 230 meters
PART A:
Solve for the slope by solving change in y over change in x. We have (3-(-5)/(-2-2) = 8/-4=-2
PART B:
Change in to y=mx+b: -5y = -2x-10. Divide all terms by -5: y = 2/5x + 2. The slope is 2/5 and the y-intercept is 2.
PART C:
Remembering from part a that m=change in y/change in x, we have the equation: -4=1-(-9)/0-x. If we simplify, we have -4=10/0-x. If we multiply both sides from 1/10 we have: -2/5 = -x. So, x = 2/5.
PART D:
We can use point-slope form first:
y-5=-7(x+1). Then we solve the equation! y-5 = -7x-7. After adding 5 to both sides, we have the equation: y=-7x-2.
5) The height of a rocket after it is launched
For this case, what you should do is remember the kinematics expressions where we have:
a
v = a * t + vo
y = a * t ^ 2 + vo * t + i
Where,
a: acceleration
v: speed
y: vertical position
t: time
vo: initial speed
yo: initial position
We observe that the expression for the given position is given by a quadratic expression.
