Question

Find the slope intercept equation that passes through (-1,2) and is perpendicular to the line with the equation 6y-x=12

Answer 1

6y - x = 12 //Solve for y.

6y = x + 12

y = x/6 + 2

Slope = m = 1/6

For the second which is perpendicular to line one has a slope of -6.

NOTE: Perpendicular line has negative reciprocal slope. 1/6 negative reciprocal would be -6.

Second line:

m = -6

point = (-1,2)

y - y1 = m(x - x1) //Plug in m and point in place of (x1,y1).

y - 2 = -6(x - -1)

y - 2 = -6x -6

y = -6x -6 +2

y = -6x - 4

//Hope it helps