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3 years ago

Which of the following statements about lipids and carbohydrates is true?

1 answer:

4 0

Answer : Lipids and carbohydrates are both made from carbon, hydrogen, and oxygen, but lipids have less oxygen (Option B)

Carbohydrates are biomolecules composed of carbon (C), hydrogen (H), and oxygen (O) in a 1:2:1 ratio, respectively.

Carbohydrates can be divided regarding the number of monomers in the biomolecule into monosaccharides, disaccharides, and polysaccharides.

Explanation:

hope this answer will helps you !

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A ball is dropped from rest out of a high window in a tall building for 5 seconds. Assuming we ignore air resistance and assume

lara [203]

Answer:

what is the upwards force?

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3 years ago

Read 2 more answers

PLEASE HURRY

VLD [36.1K]

Answer:

Wilhelm Conrad Roentgen (1845-1923)

Antoine Henri Becquerel (1852-1908)

Pierre (1859-1906) and Marie (1867-1934) Curie

Explanation:

Wilhelm Conrad Roentgen (1845-1923)

Contribution: Discovery of x-rays in 1901.

Antoine Henri Becquerel (1852-1908)

Contribution: He discovered that radioactivity is the separation of x-rays and document and the difference between two.

Pierre (1859-1906) and Marie (1867-1934) Curie

Contribution: She discovered Polonium and Radium in1911

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3 years ago

Which of the following is not a concern regarding waste

juin [17]

I believe it is noise pollution

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3 years ago

What is the angular displacement of a minute hand of a clock after 3 minutes?

Inessa [10]

Answer:

π/10 rads

Explanation:

It takes an hour (60 minutes) for the minute's hand to turn a full circle or achieve an angular rotation of

2πl rad.

Now, number of periods of 3 minutes in an hour is;

Number of periods = 60/3 = 20 periods

Thus, 3 minutes rotation accounts for 1/20 of 2π the rotation of the minute's hand in an hour.

Thus;

Angular displacement = (1/20) * 2π = π/10 rads

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2 years ago

A dog, with a mass of 10.0 kg, is standing on a flatboat so that he is 22.5 m from the shore. He walks 7.8 m on the boat toward

marissa [1.9K]

Answer:16.096

Explanation:

Given

mass of dog $\left ( m_d\right )=10kg$

mass of boat $\left ( m_b\right )=46kg$

distance moved by dog relative to ground= $x_d$

distance moved by boat relative to ground= $x_b$

Distance moved by dog relative to boat=7.8m

There no net force on the system therefore centre of mass of system remains at its position

0= $m_d\times x_d+m_b\dot x_b$

0= $10\times x_d+46\dot x_b$

$x_d=-4.6x_b$

i.e. boat will move opposite to the direction of dog

Now

$|x_d|+|x_b|=7.8$

substituting $x_d$ value

$5.6|x_b|=7.8$

$|x_b|=1.392m$

$|x_d|=6.4032m$

now the dog is 22.5-6.403=16.096m from shore

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3 years ago