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ollegr [7]
3 years ago
11

A boat is able to move through still water at 20 m/s. It makes a round trip to a town 3.0 km upstream. If the river flows at 5m/

s ,the time required for this round trip is:
a) 120s
b) 150s
c) 200s
d) 300s
e) 320s​
Physics
2 answers:
cricket20 [7]3 years ago
4 0

Answer:

Time required for round trip is 320 s.

Explanation:

Given :

Velocity of boat in still water , v = 20 m/s.

Velocity of river , V = 5 m/s.

In the given question boat make round trip to a town 3 km upstream.

Therefore, Total time = time taken in upstream + time taken in upstream.

We know , t=\dfrac{D}{v}   ( here all have their usual meaning ).

Total time , t=\dfrac{3000}{(20-5)}+\dfrac{3000}{(20+5)}    ( upstream velocity = 20-5 = 15 m/s.

                                                              downstream velocity = 20+5 = 25 m/s)

                   t=200+120=320\ s.

Hence, this is the required solution.

Salsk061 [2.6K]3 years ago
3 0

Answer:

Option e) 320 s

Explanation:

Here, distance = 3.0 km = 3000 m

The velocity of boat when it is going upstream;

Upstream velocity = velocity of boat in still water - velocity of river flow

So, Upstream velocity =20m/s-5m/s=15m/s

So,Time to go upstream

(t_{1}) =\frac{Distance}{Velocity}=\frac{3000m}{15m/s} =200 s

The velocity of boat when it is going downstream;

Downstream velocity = velocity of boat in still water + velocity of river flow

So, Downstream velocity =20m/s+5m/s=25m/s

So,Time to go downstream

(t_{2}) =\frac{Distance}{Velocity}=\frac{3000m}{25m/s} =120 s

So, total time (t) = t_{1}+t_{2}=200s+120 s=320s

Option E is the correct answer.

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Initial velocity (u) = 2.20 m/s.

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Acceleration (a) = 84.44 m/s²

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36 = 4.4 + 168.88s

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31.52 = 168.88s

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A football player with a mass of 88 kg and a speed of 2.0 m/s collides head-on with a player from the opposing team whose mass i
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Explanation:

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