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3 years ago

3x(x-2)-x^2+4=0 Help

Mathematics

1 answer:

antoniya [11.8K]3 years ago

3 0

Answer:

x=2,1 solving with quadratic formula

Step-by-step explanation:

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What is 15% of 60? Create a model to prove your answer

xeze [42]

Answer:

25%

Step-by-step:

Convert fraction (ratio) 15 / 60 Answer: 25%

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2 years ago

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Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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2 years ago

You collect the following data for explanatory variable A and response variable B:

wolverine [178]

Answer:

Step-by-step explanation:

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2 years ago

What is the complement of an angle that measures 43 deegress ?

ANTONII [103]

complementary angles sum up to 90°.

so if one of them is 43°, then the other is just 90 - 43 = 47°.

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3 years ago

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5. Graph the given system of linear inequalities on the coordinate plane below. (2 points)sy <-3x - 4< 21-15NA11 2 3 4 5 6

xxTIMURxx [149]

ANSWERS

(5) Graph:

(6) Solutions: (-1, -5) and (-2, -7)

Not solutions: (1, 1) and (-4, -3)

EXPLANATION

(5) To graph this system, first, we have to graph each of the inequalities. Both are linear, so we have to graph each line with a dashed line - this is because they are "less than" the line, so the line is not included, and shade the area below each of them.

The first inequality is y < -3x-4,

The second inequality is y < 2x - 1,

The graph of the system is the area shared by both graphs,

(6) Any point that is inside the shaded area is a solution of the system. For example, points (-1, -5) and (-2,-7) are solutions to the system.

On the other hand, any point outside that area, or on the dashed lines is not a solution. For example, points (1, 1) and (-4, -3) are not solutions

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10 months ago