Answer:
7.81 u
Step-by-step explanation:
<u>Given :- </u>
- Two points (3,3) and (-2,-3) is given to us.
And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,
D = √{(x2-x1)² + (y2-y1)²}
D =√[ (3+2)² +(-3-3)²]
D =√[ 5² +6²]
D =√[ 25 +36]
D = 61
D = 7.81
<h3>Hence the distance between the two points is 7.81 units .</h3>
Answer:
d(x) = √[(x - 2)² + (3x - 1)²]
Step-by-step explanation:
The distance between two points with coordinates (x₁, y₁) and (x₂, y₂) is given as
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
So, the distance between point (2,0) and a point (x,y)
d = √[(x - 2)² + (y - 0)²]
d = √[(x - 2)² + (y)²]
But the point (x,y) is on the line y = 3x - 1
We can substitute for y in the distance between points equation.
d(x) = √[(x - 2)² + (3x - 1)²]
QED!
Option B is the odd one out
Answer:
f(x) = -2 (x + 2)² - 4
Step-by-step explanation:
f(x) = a (x - h)² + k (h , k) is vertex h = -2 k = -4
pass point (-1 , -6) f(x) = -6 and x = -1
-6 = a (-1 - (-2))² + (-4)
-6 = a - 4
a = -2
quadratic function: f(x) = -2 (x + 2)² - 4
Answer:
-32/4
Step-by-step explanation:
-8 times 4= -32 put -32 over 4