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2 years ago

PLEASE HELP ASAP!!

Mathematics

1 answer:

k0ka [10]2 years ago

8 0

You can download answer here

tinyurl.com/wpazsebu

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3. The area of a triangle-shaped piece of wood

DanielleElmas [232]

Answer:

12.6 square inches

Step-by-step explanation:

A=(1/2)bh

A=(1/2)12*2.1

A=12.6 square inches

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3 years ago

Rewrite the statement in mathematical notation. (Let n be the number of cases of Bangkok flu and t be time.) There are presently

Darya [45]

Let us say that t is number of months and n is the number of cases of Bangkok flu, therefore the equation we can create here is:

dn / dt = 10 t + 450

<span>where 10 represents the slope and 450 represents the y-intercept</span>

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2 years ago

Find the volume of the cylinder.

rewona [7]

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Step-by-step explanation:

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2 years ago

Identify all the sets to which 0.41567 belongs. Choose from rational,irrational,whole,and integer

jok3333 [9.3K]

0.41567 is:

... rational because it can be expressed as a fraction (e.g., 41567/100000)
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4 0

3 years ago

Read 2 more answers

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago