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vazorg [7]
3 years ago
7

Just the last two ones please and thank you if you awnsered this

Mathematics
1 answer:
Rudik [331]3 years ago
8 0
Number 1 is twenty and number two is fifty six
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Angie divides the polynomial function f(x)=x3+3x2−7x−21 by (x + 3). What can she conclude from the fact that the remainder is eq
iren [92.7K]

Answer:

See below

Step-by-step explanation:

<u>Given function</u>

  • f(x)=x³ + 3x²- 7x - 21

<u>We can find its factors:</u>

  • x³ + 3x² - 7x - 21 =
  • x²(x + 3) - 7(x + 3) =
  • (x² - 7)(x + 3)

We can conclude that the given polynomial function is fully divisible by (x + 3) and the quotient is (x² - 7)

Also one of zeros of the function is -3

8 0
2 years ago
2(v + 1). Simplify the expression
serg [7]

Answer:

2v+2

Step-by-step explanation:

8 0
2 years ago
F(x)=-2(x-3)(x+5) convert quadratic functions to standard form​
jasenka [17]

Answer:

The answer is: f(x) = -2x^2 - 4x + 30

Step-by-step explanation:

Given:

f(x)=-2(x-3)(x+5)

Solve (x-3)(x+5) first, then multiply by -2:

f(x) = -2[(x - 3)(x + 5)]

f(x) = -2[x^2 -3x + 5x - 15]

f(x) = -2[x^2 + 2x - 15]

f(x) = -2x^2 - 4x + 30

Hope this Helps!! Have an Awesome Day!! (-:

4 0
3 years ago
Solve for x.<br> (17x - 23)<br> (&amp;r - 4)*<br> -(3x + 17)
Finger [1]

Answer:

17rx2−23rx−71x+75

Step-by-step explanation:

(17x−23)(xr−4)−(3x+17)

=(17x−23)(xr−4)+−1(3x+17)

=(17x−23)(xr−4)+−1(3x)+(−1)(17)

=(17x−23)(xr−4)+−3x+−17

=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)

=17rx2+−23rx+−71x+75

6 0
3 years ago
Need to know answers in box
leonid [27]
Min = 31
med = 44
max = 57
lq = 38
uq = 51
iqr = 13
3 0
3 years ago
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