The particle with charge q is now released and given a quick push; as a result, it acquires speed v. Eventually, this particle e
nds up at the center of the original square and is momentarily at rest. If the mass of this particle is m, what was its initial speed v?Express your answer in terms of q, d, m, and appropriate constants. Use k instead of 14πϵ0. The numeric coefficient should be a decimal with three significant figures.
1 answer:
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Answer:
81.8 m/s
Explanation:
The initial velocity of the plane is:
(toward east)
So, decomposing along the x- and y- directions:
(we took east as positive x-direction and north as positive y-direction)
The acceleration is
(northwest, so the angle with the positive x-direction is 135 degrees)
Decomposing it along the two directions:
So the two components of the velocity after a time t = 25.0 s will be
So, the magnitude of the velocity of the plane will be