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Arada [10]
3 years ago
10

What is the are of the following figure if AC = 12, AD = 16.

Mathematics
1 answer:
Degger [83]3 years ago
7 0

Answer:

116

Step-by-step explanation:

∆ABC

A = ½bh = ½ × 12 × 6 = 36

∆ACD

A = ½bh = ½ × 16 × 7 = 56

∆ADE

A = ½bh = ½ × 16 × 3 = 24

ABCDE  

A = ∆ABC + ∆ACD +∆ADE = 36 + 56 + 24 = 116

The area of the figure is 116 square units.

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