Answer:
The first thing you do is:
Step-by-step explanation:
How to calculate 60 divided by 19
Here we will show you step-by-step with detailed explanation how to calculate 60 divided by 19 using long division.
Before you continue, note that in the problem 60 divided by 19, the numbers are defined as follows:
60 = dividend
19 = divisor
Step 1:
Start by setting it up with the divisor 19 on the left side and the dividend 60 on the right side like this:
1 9 ⟌ 6 0
Step 2:
The divisor (19) goes into the first digit of the dividend (6), 0 time(s). Therefore, put 0 on top:
0
1 9 ⟌ 6 0
Step 3:
Multiply the divisor by the result in the previous step (19 x 0 = 0) and write that answer below the dividend.
0
1 9 ⟌ 6 0
0
Step 4:
Subtract the result in the previous step from the first digit of the dividend (6 - 0 = 6) and write the answer below.
0
1 9 ⟌ 6 0
- 0
6
Step 5:
Move down the 2nd digit of the dividend (0) like this:
0
1 9 ⟌ 6 0
- 0
6 0
Step 6:
The divisor (19) goes into the bottom number (60), 3 time(s). Therefore, put 3 on top:
0 3
1 9 ⟌ 6 0
- 0
6 0
Step 7:
Multiply the divisor by the result in the previous step (19 x 3 = 57) and write that answer at the bottom:
0 3
1 9 ⟌ 6 0
- 0
6 0
5 7
Step 8:
Subtract the result in the previous step from the number written above it. (60 - 57 = 3) and write the answer at the bottom.
0 3
1 9 ⟌ 6 0
- 0
6 0
- 5 7
3
Answer:
<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>
Step-by-step explanation:
For a quadratic equation:

The sum of the roots is -b and the product is c. Note the leading coefficient is 1.
We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:
P=2(L+W)=36
A=L.W=80
Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.
Thus we use the semi perimeter instead as P/2=L+W=18
The quadratic equation is, then:

Factoring by finding two numbers that add up to 18 and have a product of 80:

The solutions to the equation are:
x=10, x=8
Thus, the dimensions of the metal plate are 10 dm and 8 dm.
C
If we drew a line of best fit, the gradient would be roughly equal to 1, and the y intercept would be at around -4
Copper: Nickel = 4:1
a) How much copper needed for 20 kg nickel
C:N = 4: 1
C:20 = 4:1
C/20 = 4/1 Cross Multiply
C*1 = 4*20
C = 80
80kg Copper would be needed.
b) How much Nickel would be needed for 20 kg of Copper
C:N = 4: 1
20:N = 4:1
20/N = 4/1 Cross Multiply
4*N = 1*20
4N = 20 Divide both sides by N.
N = 20/4 = 5
5kg Nickel would be needed.
Answer:
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Step-by-step explanation: